Answer:
y = C₂ e²ᵗ + e⁻ᵗ [C₁ - (5t/3)]
Step-by-step explanation:
y" - y' - 2y = 5e⁻ᵗ
The total solution of this differential equation will be a sum of its complimentary and particular solutions.
y = y꜀ + yₚ
The complimentary or homogenous solution is a solution of
y" - y' - 2y = 0
y꜀ = Ay₁ + By₂
Solving this part in the attached image, we obtain
y₁ = e⁻ᵗ and y₂ = e²ᵗ
The particular solution can be obtained using the method of variation of parameters and the method of undetermined coefficients.
The method of variation of parameters is used and explained in the page 1, 2 and page 3 of the attached images.
The method of undetermined coefficients is then used to check if the solution obtained is correct.
With y = C₂ e²ᵗ + e⁻ᵗ [C₁ - (5t/3)],
y' and y'' were obtained and put in the equation, and the answer obtained was 5e⁻ᵗ.
So, Proved!
y = C₂ e²ᵗ + e⁻ᵗ [C₁ - (5t/3)]
Hope this helps!!!
(hog)(x)
Step-by-step explanation:
(hog)(x) = h(g(x))
= h(3x + 7)
h(x) = x + 8
h(3x + 7) = 3x + 7 + 8
h(3x + 7) = 3x + 15
(hog)(x) = 3x + 15
Answer:
Yes indeed, at least I'm pretty sure.
Step-by-step explanation:
4 is half of 2, and 3 is half of 6. you could write them as equal, just like 1/2 and 2/4 fractions.
Answer:
6-3i
Step-by-step explanation:
First, you need to get rid of perenthesis. Use destributuve property to do so.
Then, add the add the same types of integers(whole numbers and numbers with variables)
after that, you get your answer!
2y-4x=7 is the equation are parallel show break down