The distance from point A to point B is known as the A) wave height. B) wavelength. C) amplitude. D) volume.

Answers

Answer 1
Answer:

Answer:

The answer is B wavelength

Answer 2
Answer:

Answer:B) wavelength

Explanation:The distance from point A to B is the wavelength. It can be measured from crest to crest or trough to trough.


Related Questions

For an isothermal process, the work done by or on a system of ideal gas is equal to the change in what? A. The work done is equal to the change in internal energy.B.The work done is equal to the change in heat energy.C.The work done is equal to change in entropy.D.The work done is equal to the change in pressure.
Which of the following colors is associated with the lowest temperature? Explain your reasoning.A. Blue B. Green C. Yellow D. Red
Dirty windshields __________.a. reflect light into your eyes, causing glareb. reflect light away from the vehicle, making the road appear dimc. will not become foggedd. none of the above
A. B. C. D.-___________
The equation h=80t-16t^2 models the height h in feet reached in t seconds by an object propelled straight up from the ground at a speed of 80 ft/s. use the discriminant to find whether the object will ever reach a height of 90 ft

What are different type of plastids explain them?​

Answers

Answer:

types of plastids

chloroplasts

chromoplasts

gerontoplasts

leucoplasts

Explanation:

ans

State the relationship between degrees Celsius and kelvins

Answers

Kelvin is a unit of absolute temperature and is often used in measurements and it can also be associated with degrees Celsius. 0 Kelvin is equivalent to -273.15 degrees Celsius.

In order to solve for either unit of temperature, the equation is:

T(Kelvin)= T(degrees Celsius) + 273.15
T(degrees Celsius) = T(Kelvin) - 273.15

Talking in to a microphone which energy dose your voice change as?

Answers

The microphone changes the mechanical energy of the sound wave into electric energy.

Can Someone Help ? !5 Points!!!If the weight of displaced water is greater than the weight of an object, then the object will:

A. float
B. sink
C. sink, then float

An object will float when:

A. buoyant force is equal to the weight of the object
B. buoyant force is less than the weight of the object
C. density is equal to the weight of the object
D. density is greater than the weight of the object

What is the buoyancy force on a 15 g object which displaces 60 mL of water? (Remember to change mL of water to grams and grams to kg)

A. 900 N
B. 25 N
C. 0.59 N
D. 0.25 N

An object has a density of 20 g/cm3. When placed in a cylinder, it displaces 5 mL of water. What is the mass of the object?

A. 0.25 g
B. 4.0 g
C. 100.0 g

Substance has a mass of 16.2 grams. It displaces 8.1 grams of water. What is its specific gravity?

A. 2.0
B. 5.5
D. 131.22

Answers

1) A. float

There are two forces acting on an object in the water: the weight of the object (downward) and the buoyancy (upward), which is equal to the weight of displaced water. If the weight of displaced water is greater than the weight of the object, it means that there is a net force directed upward, so the object will float.

2) A. buoyant force is equal to the weight of the object

As stated in the previous question, there are only these two forces acting on an object in the water (buoyant force and weight of the object), so if the two forces are equal, then the object is in equilibrium, so it will float.

3) C. 0.59 N

The buoyancy force is given by:

B=\rho_L V_d g

where

\rho_L = 1000 kg/m^3 is the density of the liquid (water)

V_d=60 mL=6 \cdot 10^(-2) L=6 \cdot 10^(-5) m^3 is the volume of displaced water

g=9.8 m/s^2 is the acceleration of gravity

Substituting numbers into the formula, we find

B=(1000 kg/m^3)(6 \cdot 10^(-5) m^3)(9.8 m/s^2)=0.59 N

4) C. 100.0 g

The density of the object is 20 g/cm^3, which is greater than the density of the water (1 g/cm^3): this means that the object will sink, so its volume is equal to the volume of displaced water.

Therefore, we have:

- object's density: \rho=20 g/cm^3

- object's volume: V=5 mL=5 cm^3

so, the mass of the object is

m=dV=(20 g/cm^3)(5 cm^3)=100.0 g

5) A. 2.0 g

The specific gravity of an object is given by the ratio between its density (\rho) and the density of a reference substance (\rho_W), in this case water:

SG=(\rho)/(\rho_W)

whe can rewrite each density as the ratio between mass and volume:

SG=(m_o /V_o)/(m_w/V_w)

where the suffix o refers to the object, while the suffix w refers to the water. However, if we assume that the object is completely in the water, the two volumes are equal, so we can simplify the formula:

SG=(m_o)/(m_w)=(16.2 g)/(8.1 g)=2.0

When Jenny writes, the pencil exerts a force of 5n on the paper. The area of the contact is 0.5mm square. Calculate the pressure.

Answers

p= F/A (pressure= Force/ Area) so 5/0.5 = 10N/mm. Pressure is 10N/mm

what is the net force if you push a cart to the right with 5N of force and a friend pushes the cart to the left with 5N of force

Answers

The net force will be zero. Since the forces are in opposite direction and equal amount, they will cancel out.