MATHEMATICS COLLEGE

Help, ill mark brainliest

Answers

Answer 1

Answer:

Answer: FIRST OPTION.

Step-by-step explanation:

First, it is important to remember that the Slope-Intercept form of the equation of a line is the shown below:

$y=mx+b$

Where "m" is the slope of the line and "b" is the y-intercept.

By definiton, given a System of Linear equations, if they are exactly the same line, then the System of equations have Infinely many solutions.

In this case you have the following System of Linear equations given in the exercise:

$\left \{ {{y=-2x+5} \atop {y=ax+b}} \right.$

So, since you need the system has Infinite solutions, you know that the slope and the y-intercept of both lines must be equal.

Therefore, you can identify that the value of "a" and "b" must be the following:

$a=-2\n\nb=5$

So the Linear System would be the shown below:

$\left \{ {{y=-2x+5} \atop {y=-2x+5}} \right.$

Related Questions

(4k^4 + 2 - 3k) + (5k^4 + k - 8)
The parallelogram shown below has an area of 15 units^2Find the missing height.
Question 17Solve the following problem below. Write your final answer in scientific notation7.2 x 104 x 10-9A1.8 x 102B1.8 x 10-2С1.8 x 10-8D1.8 x 10-8
13. Mr. Smith teaches history and math classes. He has 25 students in both classes combined. He has 17 students in the math class and 15 students in the history class. Is it possible that 12 stu- dents are enrolled in both his history and his math classes?!
Helppp meeYou walk into a restaurant. In the room there are 10 people who are 21 years old , 3 people are 26 years old 7 people are 29 years old and 9 people who are 31 years old. 17 are men. how many people are in the restaurant.

Consider the following system of equations:Equation 1: 82 + 2y = 30
Equation 2: 70 + 2y = 24
Which variable pair should we try to eliminate?
The x's because the coefficients are the same.
The y's because the coefficients are the same.
The x's because the coefficients are different?
The y's because the coefficients are different?

Answers

The correct answer is: "The y's because the coefficients are the same."

Further explanation:

we always try to eliminate the variable from the system of equations which involves lesser calculations and complexity.

Assuming that Given equations are:

Equation 1: 82x + 2y = 30

Equation 2: 70x + 2y = 24

we can see that the coefficients of x are very large and different. While the coefficients of y are same. We can only subtract the equations to eliminate y.

Hence,

The correct answer is: "The y's because the coefficients are the same."

Keywords: Linear equations, variables

Learn more about linear equations at:

#LearnwithBrainly

According to a survey conducted in a certain year by the Federal Communications Commission (FCC) of 3005 adults who were home broadband users, 34.5% of those surveyed had switched their service over the past 3 years. Of those who had switched service in the past 3 years, 51% were very satisfied, 39% were somewhat satisfied, and 10% were not satisfied with their service. Of the 65.5% who had not switched service in the past 3 years, 48% were very satisfied, 43% were somewhat satisfied, and 9% were not satisfied with their service.(a) What is the probability that a participant chosen at random had not switched service in the past 3 years and was very satisfied with their service?

(b) What is the probability that a participant chosen at random was not satisfied with their service?

Answers

Answer:

(a) The probability is 31.44%

(b) The probability is 9.345%

Step-by-step explanation:

The probability for part (a) is calculated as a multiplication of:

65.5% * 48% = 31.44%

Where 65.5% is the percentage of participants that had not switched service in the past 3 years and 48% are the percentage of those 65.5% that were very satisfy. So, the 31.44% of the participants had not switched service in the past 3 years and were very satisfied with their service.

Then, for part b, we have 2 cases:

Case 1: A person that had not had switched service in the past 3 years and was not satisfied with their service
Case 2:A person that had not switch in the past 3 years and was not satisfied with their service.

So, the probability is calculated as a sum of these two probabilities.

Therefore, the probability for case 1 is calculated as:

34.5% * 10% = 3.45%

Where 34.5% is the percentage of participants that had switched service in the past 3 years and 10% are the percentage of those 34.5% that were not satisfy.

At the same way, the probability for case 2 is:

65.5% * 9% = 5.895%

Finally, the probability that a participant chosen at random was not satisfied with their service is the sum of 3.45% and 5.895%. That is:

3.45% + 5.895% = 9.345%

consider the quadratic form q(x,y,z)=11x^2-16xy-y^2+8xz-4yz-4z^2. Find an orthogonal change of variable that eliminates the cross product in q(x,y,z) and express q in the new variables.

Answers

Answer:

$q(x,y,z)=16x^(2)-5y^(2)-5z^(2)$

Step-by-step explanation:

The given quadratic form is of the form

$q(x,y,z)=ax^2+by^2+dxy+exz+fyz$ .

Where $a=11,b=-1,c=-4,d=-16,e=8,f=-4$ .Every quadratic form of this kind can be written as

$q(x,y,z)={\bf x}^(T)A{\bf x}=ax^2+by^2+cz^2+dxy+exz+fyz=\left(\begin{array}{ccc}x&y&z\end{array}\right) \left(\begin{array}{ccc}a&(1)/(2) d&(1)/(2) e\n(1)/(2) d&b&(1)/(2) f\n(1)/(2) e&(1)/(2) f&c\end{array}\right) \left(\begin{array}{c}x&y&z\end{array}\right)$

Observe that $A$ is a symmetric matrix. So $A$ is orthogonally diagonalizable, that is to say, $D=Q^(T)AQ$ where $Q$ is an orthogonal matrix and $D$ is a diagonal matrix.

In our case we have:

$A=\left(\begin{array}{ccc}11&((1)/(2))(-16) &((1)/(2)) (8)\n((1)/(2)) (-16)&(-1)&((1)/(2)) (-4)\n((1)/(2)) (8)&((1)/(2)) (-4)&(-4)\end{array}\right)=\left(\begin{array}{ccc}11&-8 &4\n-8&-1&-2\n4&-2&-4\end{array}\right)$

The eigenvalues of $A$ are $\lambda_(1)=16,\lambda_(2)=-5,\lambda_(3)=-5$ .

Every symmetric matriz is orthogonally diagonalizable. Applying the process of diagonalization by an orthogonal matrix we have that:

$Q=\left(\begin{array}{ccc}(4)/(√(21))&-(1)/(√(17))&(8)/(√(357))\n(-2)/(√(21))&0&\sqrt{(17)/(21)}\n(1)/(√(21))&(4)/(√(17))&(2)/(√(357))\end{array}\right)$

$D=\left(\begin{array}{ccc}16&0&0\n0&-5&0\n0&0&-5\end{array}\right)$

Now, we have to do the change of variables ${\bf x}=Q{\bf y}$ to obtain

$q({\bf x})={\bf x}^(T)A{\bf x}=(Q{\bf y})^(T)AQ{\bf y}={\bf y}^(T)Q^(T)AQ{\bf y}={\bf y}^(T)D{\bf y}=\lambda_(1)y_(1)^(2)+\lambda_(2)y_(2)^(2)+\lambda_(3)y_(3)^(2)=16y_(1)^(2)-5y_(2)^(2)-5y_(3)^2$

Which can be written as:

$q(x,y,z)=16x^(2)-5y^(2)-5z^(2)$

The nth term of a sequence is -3-3n what is the 6th term

Answers

Answer:

-21

Step-by-step explanation:

if for s(n) = -3-3n

then s(6) = -3-3*6 = -3-18 = -21

between which two numbers is the whole number qoutient of 88 divided by 5 write the numbers in the boxes (the number choices: 5, 10, 15, 20, 25)

Answers

Answer:

15 and 20

Step-by-step explanation:

When dividing 88 by 5 we wil have;

88/5

= 17 3/5

= 17 + 0.6

= 17.6

So we are to find the two numbers that 17.6 falls in between

From the given option 17.6 falls between 15 and 20. Hence the required numbers are 15 and 20

A paint manufacturer made a modification to a paint to speed up its drying time. Independent simple random samples of 11 cans of type A (the original paint) and 9 cans of type B (the modified paint) were selected and applied to similar surfaces. The drying times, in hours, were recorded. The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B: 4.90 hrs < μ1 - μ2 < 17.50 hrs
What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.
C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.
D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answers

This question is not complete, I got the complete one from google as below:

The summary statistics are as follows.

Type A Type B

x1 = 76.3 hrs x2 = 65.1 hrs

s1 = 4.5 hrs s2 = 5.1 hrs

n1 = 11 n2 = 9

The following 98% confidence interval was obtained for μ1 - μ2, the difference between the mean drying time for paint cans of type A and the mean drying time for paint cans of type B:

4.90 hrs < μ1 - μ2 < 17.50 hrs

What does the confidence interval suggest about the population means?

A. The confidence interval includes 0 which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

B. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

C. The confidence interval includes only positive values which suggests that the two population means might be equal. There doesn't appear to be a significant difference between the mean drying time for paint type A and the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

D. The confidence interval includes only positive values which suggests that the mean drying time for paint type A is smaller than the mean drying time for paint type B. The modification does not seem to be effective in reducing drying times.

Answer:

Option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

Step-by-step explanation:

The 98% confidence interval for the difference in mean drying times of the two types of paints is (4.90, 17.50). This implies that Type A takes between 4.90 and 17.50 hours more to dry than type B paint.

Thus, option B is correct - the confidence interval includes only positive values which suggests that the mean drying time for paint type A is greater than the mean drying time for paint type B. The modification seems to be effective in reducing drying times.

Other Questions

A baseball is hit inside a baseball diamond with a length and width of 90 feet each. What is the probability that the ball will bounce on the pitchers mound, if the diameter of the mound is 18 feet? Assume that the ball is equally likely to bounce anywhere in the infield. When applicable, leave your answer in terms of pie and include all necessary calculations.

Consider a binomial experiment with n = 20 and p = .70. If you calculate the binomial probabilities manually, make sure to carry at least 4 decimal digits in your calculations. a) Compute f(12) (to 4 decimals). b) Compute f(16) (to 4 decimals). c) Compute P(x 16) (to 4 decimals). d) Compute P(x 15) (to 4 decimals). e) Compute E(x). 14 f) Compute Var(x) (to 1 decimal) and (to 2 decimals). Var(x) o

In a right triangle, Angle A and B are acute. If tan B= 2, what is cos B? Round to three decimal places.Show work plzzz!!!

Which table represents a function?