Consider a binomial experiment with n = 20 and p = .70. If you calculate the binomial probabilities manually, make sure to carry at least 4 decimal digits in your calculations.

a) Compute f(12) (to 4 decimals).
b) Compute f(16) (to 4 decimals).
c) Compute P(x 16) (to 4 decimals).
d) Compute P(x 15) (to 4 decimals).
e) Compute E(x). 14
f) Compute Var(x) (to 1 decimal) and (to 2 decimals).
Var(x)
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Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

Given that X is binomial n=20: p=0.70

a) Compute f(12) (to 4 decimals).

=0.1144

b) Compute f(16) (to 4 decimals).

=0.1304

c) Compute P(x <16) (to 4 decimals).

=0.7624

d) Compute P(x <15) (to 4 decimals).

=0.5836

e) Compute E(x). =np = 14

f) Compute Var(x) (to 1 decimal) and (to 2 decimals).

Var(x)=npq=4.2


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Answers

Answer:

1) Y-6=-3/2(X-0)     2) Y= -3/2x+6   3) 3x+2y=12

Step-by-step explanation:

A certain analytical method for the determination of lead yields masses for lead that are low by 0.5 g. Calculate the percent relative error caused by this deviation for each measured mass of lead. Report the percent relative error with the correct number of significant figures.

Answers

Question Continuation

if the measured weight of lead in the sample is

a.) 764.9g lead

b.)226.3g lead

c.) 53.5g lead

Answer:

a.

Relative Error = 0.065

b.

Relative Error = 0.221

c.

Relative Error = 0.935

Step-by-step explanation:

Given

Absolute Error = 0.5g

Relative error = absolute error/magnitude of measurement.

Relative error % = Relative error * 100

a.

Relative Error = 0.5/764.9 * 100

Relative Error = 50/764.9

Relative Error = 0.065

b.

Relative Error = 0.5/226.3 * 100

Relative Error = 50/226.3

Relative Error = 0.221

c.

Relative Error = 0.5/53.5 * 100

Relative Error = 50/53.5

Relative Error = 0.935

Final answer:

In Chemistry, the percent relative error is calculated by taking the absolute value of the error divided by the original measurement, and then multiplying by 100%. In this case, for a measured value of lead, the percent relative error would be (0.5 g / measured mass) * 100%.

Explanation:

The percent relative error in any measurement is calculated by taking the absolute value of the error divided by the measured value, all multiplied by 100% to get the result in percent forms. In this case, the absolute error is always 0.5 g (which means the values are consistently 0.5 g less than expected). The percent relative error would be calculated as follows:

  • For a measured value, say M grams, the percent relative error would be (0.5 g / M) * 100%.

Keep in mind, the relative error varies with each measured mass. Therefore, for each different measured mass of lead, you would substitute that value in place of M in the above formula to calculate the respective percent relative error.

Learn more about percent relative error here:

brainly.com/question/32355610

#SPJ3

In a sample of 41 water specimens taken from a construction site, 23 contained detectable levels of lead. A 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is 0.409


Required:
Construct a confidence interval for the proportion of water specimens that contain detectable levels of lead.

Answers

Answer:

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Step-by-step explanation:

6th grade math look at the pictures

Answers

Answer:

2. 17.624

3. 9.72

4. 14.3

5. 2.11

8. 5,105.16

10. 124.7

Step-by-step explanation:

Answer:

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Step-by-step explanation:

Whats 10293 x 384? Its really hard!

Answers

Answer:

3,952,512

Step-by-step explanation:

The profit on a teddy bear can be found by using the function P(x) = - 2x2 + 35x - 99 where x is the price of the bear.Calculate the price that maximizes profit.

Answers

Answer:

x=8.75

Step-by-step explanation:

The price x that maximizes profit is the maximum value of the function, and the maximum value of the function is located at a point where the first derivative of the function is equal to zero. The first derivative is:

P(x) = - 2x^2+35x-99\nP'(x)=-2(2)x^((2-1))+35(1)-0\nP'(x)=-4x+35

Using P'(x)=0:

0=-4x+35\n4x=35\nx=35/4\nx=8.75

The minimum value of the function is also at a point where the first derivative of the function is equal to zero. To differentiate if x=8. is a minimum or a maximum obtain the second derivative and evaluate it at x=8.75 if the value P''(x)>0 x is minimum and if P''(x)<0 x is a maximum.

P'(x)=-4x+35\nP''(x)=-4(1)\nP''(x)=-4

Evaluating at x=8.75:

P''(8.75)=-4

Therefore, x=8.75 is the maximum value of the function and it is the price that maximizes profit.