The image illustrates the Pythagorean theorem because adding the areas of the two smaller squares equals the area of the largest square.
Pythagoras's theorem states that in a right-angled triangle, the square of one side is equal to the sum of the squares of the other two sides.
As per the given question, the required solution would be as:
The 2nd greatest square's area is 64 units².
Area = l × w
Area = 8 × 8 = 64
the smallest square's area is 36units².
Area = 6 × 6 = 36
the smaller square's area combined is 64 + 36=100units².
the largest square's area is 100units².
Area = 10 × 10 = 100
The area of the largest square (100) units² equals the sum of the areas of the smaller squares (100) units².
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Answer:
The diagram illustrates the Pythagorean theorem because if you add the area of the two smaller squares it equals the area of the largest square.
Step-by-step explanation:
the 2nd biggest square's area is 64. (A=lw
A=8x8
A=64)
the smallest square's area is 36. (A=lw
A=6x6
A=36)
the smaller square's areas combined is 100. (64+36=100)
the largest square's area is 100. (A=lw
A=10x10
A=100)
the largest square's area (100) equals the smaller square's areas combined (100).