Answer: The average distance the electron can travel in microns is 1.387um/s
Explanation: The average distance the electron can travel is the distance an exited electron can travel before it joins together. It is also called the diffusion length of that electron.
It is gotten, using the formula below
Ld = √DLt
Ld = diffusion length
D = Diffusion coefficient
Lt = life time
Where
D = 25cm2/s
Lt = 7.7
CONVERT cm2/s to um2/s
1cm2/s = 100000000um2/s
Therefore D is
25cm2/s = 2500000000um2/s = 2.5e9um2/s
Ld = √(2.5e9 × 7.7) = 138744.37um/s
Ld = 1.387e5um/s
This is the average distance the excited electron can travel before it recombine
again = "false";
result = 0;
a. choice
b. again
c. result
d. none of these are Boolean variables
Answer:
C
Explanation:
Boolean Algebra deals with either a one or a zero and how to manipulate them in computers or elsewhere. The "choice" option may not work, since for text it must be enclosed in quotation marks, usually. For "again," it's text and not a 1 or 0. So, the answer is C, since this is a 0.
The program analyses a set of male and female names and displays, the combined set of names, specific names and neutral names. The program written in python 3 goes thus :
male_names = {'John', 'Bailey', 'Charlie', 'Chuck', 'Michael', 'Samuel', 'Jayden', 'Aiden', 'Henry', 'Lucas'}
#setofmalenames
female_names = {'Elizabeth', 'Meghan', 'Kim', 'khloe','Bailey', 'Jayden' , 'Aiden', 'Britney', 'Veronica', 'Maria'}
#setoffemalenames
neutral_names = male_names.intersection(female_names)
#names common to both males and females
all_names = male_names.union(female_names)
#set of all baby names ; both male and female
specific_names = male_names.symmetric_difference(female_names)
#name in one set and not in the other
print(all_names)
print(' ')
#leavesaspaceinbetweenthelines
print(specific_names)
print(' ')
print(neutral_names)
Asamplerunoftheprogramisattached.
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Answer:
Please see attachment
Explanation:
Please see attachment
(b) 75 kHz
(c) 80 kHz
(d) 160 kHz
(e) None of the above.
Answer:
Option D
160 kHz
Explanation:
Since we must use at least one synchronization bit, total message signal is 15+1=16
The minimum sampling frequency, fs=2fm=2(5)=10 kHz
Bandwith, BW required is given by
BW=Nfs=16(10)=160 kHz
Answer: 199.1 kip
Explanation:
Given that
Outer diameter is Do = 7 in
Inner diameter Di = ( Do - ( 2×0.5)) = 6 in
Length = 5000 ft = 60000 in
Now change in length of the pipe due to temperature difference
SL = L∝ΔT
= 60000 × 6.5×10^-6(140-40)
SL = 39 in
Also
sL = PL/AE
A = cross sectional area of pipe = π/4(Do^2 - Di^2)
so
P = SL×A×E / L
= (39 × π/4(7^2 - 6^2)×30000) / 60000
= 199.1 kip
compressive load applied by the pipeline on a PLET due to its thermal expansion is 199.1 kip
Answer:
Given:
operating temperature of heat engine,
Solution:
For a reversible cycle, maximum efficiency, is given by:
Now, on re designing collector, maximum temperature, changes to
, so, the new maximum efficiency,
is given by:
Answer:
A simple single-phase transformer has each winding being wound cylindrically on a soft iron limb separately to provide a necessary magnetic circuit, which is commonly referred to as “transformer core”. It offers a path for the flow of the magnetic field to induce voltage between two windings.