Answer:
temperature of first extraction 330.8°C
temperature of second extraction 140.8°C
power output=3168Kw
Explanation:
Hello!
To solve this problem we must use the following steps.
1. We will call 1 the water vapor inlet, 2 the first extraction at 100kPa and 3 the second extraction at 200kPa
2. We use the continuity equation that states that the mass flow that enters must equal the two mass flows that leave
m1=m2+m3
As the problem says, 20% of the flow represents the first extraction for which 5 * 20% = 1kg / s
solving
5=1+m3
m3=4kg/s
3.
we find the enthalpies and temeperatures in each of the states, using thermodynamic tables
Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties
4.we find the enthalpy and entropy of state 1 using pressure and temperature
h1=Enthalpy(Water;T=T1;P=P1)
h1=3457KJ/kg
s1=Entropy(Water;T=T1;P=P1)
s1=7.234KJ/kg
4.
remembering that it is a reversible process we find the enthalpy and the temperature in the first extraction with the pressure 1000 kPa and the entropy of state 1
h2=Enthalpy(Water;s=s1;P=P2)
h2=3116KJ/kg
T2=Temperature(Water;P=P2;s=s1)
T2=330.8°C
5.we find the enthalpy and the temperature in the second extraction with the pressure 200 kPav y the entropy of state 1
h3=Enthalpy(Water;s=s1;P=P3)
h3=2750KJ/kg
T3=Temperature(Water;P=P3;s=s1)
T3=140.8°C
6.
Finally, to find the power of the turbine, we must use the first law of thermodynamics that states that the energy that enters is the same that must come out.
For this case, the turbine uses a mass flow of 5kg / s until the first extraction, and then uses a mass flow of 4kg / s for the second extraction, taking into account the above we infer the following equation
W=m1(h1-h2)+m3(h2-h3)
W=5(3457-3116)+4(3116-2750)=3168Kw
Answer: Provided in the explanation section
Explanation:
Transactional Leadership - This leadership style is mainly focused on the transactions between the leader and employees. If the employees work hard, achieve the objectives and deliver the results, they are rewarded through bonuses, hikes, promotions etc. If the employees fail to achieve the desired results, they are punished by awarding lower ratings in the performance appraisal, denying opportunities etc.
In this style, leader lays emphasis on the relation with the followers.
It is a reactive style where the growth of the employee in the organization completely depends on the performance with respect to the activities and deliverables.
It is best suited for regular operations and for a settled environment by developing the existing organizational culture which is not too challenging.
It is a bureaucratic style of leadership where the leader concentrates on planning and execution rather than innovation and creation.
A transactional leader is short-term focused and result oriented. He/she doesn't consider long-term strategic objectives regarding the organization's future.
cheers i hope this helped !!
b) sketch vc and ic.
Answer:
hello your question is incomplete attached is the complete question
A) Vc = 15 ( 1 - ) , ic =
B) attached is the relevant sketch
Explanation:
applying Thevenin's theorem to find the mathematical expression for the transient behavior of Vc and ic after closing the switch
= 8 k ohms || 24 k ohms = 6 k ohms
=
= 15 v
t = RC = (10 k ohms( 15 uF) = 0.15 s
Also; Vc =
hence Vc = 15 ( 1 - )
ic = =
=
attached
The program analyses a set of male and female names and displays, the combined set of names, specific names and neutral names. The program written in python 3 goes thus :
male_names = {'John', 'Bailey', 'Charlie', 'Chuck', 'Michael', 'Samuel', 'Jayden', 'Aiden', 'Henry', 'Lucas'}
#setofmalenames
female_names = {'Elizabeth', 'Meghan', 'Kim', 'khloe','Bailey', 'Jayden' , 'Aiden', 'Britney', 'Veronica', 'Maria'}
#setoffemalenames
neutral_names = male_names.intersection(female_names)
#names common to both males and females
all_names = male_names.union(female_names)
#set of all baby names ; both male and female
specific_names = male_names.symmetric_difference(female_names)
#name in one set and not in the other
print(all_names)
print(' ')
#leavesaspaceinbetweenthelines
print(specific_names)
print(' ')
print(neutral_names)
Asamplerunoftheprogramisattached.
Learn more :brainly.com/question/9908895
Answer:
Please see attachment
Explanation:
Please see attachment
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Answer:80
Answer:
364 566 inches of class-6th from a
Answer: The average distance the electron can travel in microns is 1.387um/s
Explanation: The average distance the electron can travel is the distance an exited electron can travel before it joins together. It is also called the diffusion length of that electron.
It is gotten, using the formula below
Ld = √DLt
Ld = diffusion length
D = Diffusion coefficient
Lt = life time
Where
D = 25cm2/s
Lt = 7.7
CONVERT cm2/s to um2/s
1cm2/s = 100000000um2/s
Therefore D is
25cm2/s = 2500000000um2/s = 2.5e9um2/s
Ld = √(2.5e9 × 7.7) = 138744.37um/s
Ld = 1.387e5um/s
This is the average distance the excited electron can travel before it recombine
Answer:
The correct answer is C) Trimetric
Explanation:
The most suitable answer is a trimetric projection because, in this type of projection, we see that the projection of the three angles between the axes are not equal. Therefore, to generate a trimetric projection of an object, it is necessary to have three separate scales.