Answer:
The kinetic energy of the apple at this height is 0.49 J.
Explanation:
Mass of apple, m = 0.1 kg
It falls form a height of 1.5 meters to 1 meters. We need to find the kinetic energy of the apple at this height. As the apple is falling, the decrease in potential energy is equal to the increase in kinetic energy. Using the conservation of energy as :
So, the kinetic energy of the apple at this height is 0.49 J. Hence, this is the required solution.
The puck starts with velocity vector
Its velocity at time is
Over the 0.215 s interval, the velocity changes to
Then the acceleration must have been
which has a direction of about .
The direction of the acceleration is determined by the direction of the change in velocity. This would be calculated by subtracting the initial velocity vector from the final velocity vector. However, the calculation would involve complex trigonometric functions.
In order to find the direction of the acceleration, we need to calculate the direction of the change in velocity and that direction will be the direction of the acceleration.
To calculate the change in velocity, we subtract the initial velocity from the final velocity: (6.42 m/s, 50.0°) - (2.35 m/s, -22°). We then calculate the angle of this vector which represents the change in velocity, and hence the direction of acceleration.
However, this calculation is not straightforward because it involves vector operations and would require the use of trigonometric functions to solve. This is due to the fact that velocity is a vector, meaning it has both a magnitude and a direction. Consequently, this becomes a multi-step process involving trigonometry and physics.
#SPJ2
b. solar flares
c. coronas
d. supernovae
Answer: Solar Flares
Explanation:
to 20 m/s in 45 seconds? *
Answer:
1,803,036.67 W
Explanation:
Data provided in the question:
People per hour that can be moved by lift = 49800
Height of movement, h = 190 m
Average mass per person = 70 kg
Now,
Power = Rate of doing work
Thus,
Power = ΔU
= mgh
here,
m = total mass
g = acceleration due to gravity
or
Power = (70kg × 49800)(9.8)(190)
or
Power = 6,490,932,000 J per hour
also,
Watt = Joule/second
Therefore,
Power = 6,490,932,000 ÷ 3600
= 1803036.67 W
To estimate the maximum total power needed for Squaw Valley ski area to move 49800 people per hour on their lifts, we calculate the work done per person per hour and then divide it by the time taken to travel vertically by 190 m. The estimated maximum total power needed is 3.31 x 10^8 W.
To estimate the maximum total power needed to move 49800 people per hour on a skilift at Squaw Valley, we can calculate the work done per person per hour and then divide it by the time taken to travel vertically by 190m. The work done is equal to the potential energy gained, which is given by the formula mgh, where m is the average mass per person (70 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the vertical height gained (190 m). Multiplying this by the number of people per hour gives us the total work done per hour. Dividing this by the time taken to travel the vertical height gives us the maximum power needed. The power is given by the formula P = W/t, where W is the work done and t is the time taken.
Using the given values, we have:
Work done per person per hour: (70 kg) x (9.8 m/s^2) x (190 m) = 128660 J
Total work done per hour: 128660 J x 49800 = 6.40 x 10^9 J
Time taken to travel vertically by 190m: 190 m / (9.8 m/s^2) = 19.39 s
Maximum power needed: (6.40 x 10^9 J) / (19.39 s) = 3.31 x 10^8 W
#SPJ3
Answer:
maximum extent of a vibration or oscillation measured from the position of equilibrium.
Answer:
the maximum displacement or distance moved by a point on a vibratng body or wave measured from its equilibrium position. it is equal to one-half lenght of the vibration path.
Explanation:
hope it helps
B. Free electrons are concentrated in the P-type material and holes form in the N-type material.
C. The negative terminal of the source of voltage is connected to the N-type material within a reverse-biased setup.
D. Only a small current will flow through the diode in the forward-biased setup.