PHYSICS COLLEGE

In this example the motion is in a vertical circle. Passengers in a carnival ride travel in a circle with radius 5.0 m. The ride moves at a constant speed and makes one complete circle in a time T=4.0s. What is the acceleration of the passengers? If the ride increases in speed so that T=3.0s, what is arad? (This question can be answered by using proportional reasoning, without much arithmetic.)

Answers

Answer 1

Answer:

Answer:

a. $12.3m/s^(2)$

b. $21.93m/s^(2)$

Explanation:

From the data given, the radius is 5.0m, and the time taken to complete one circle is 4.0secs

Since the motion is in a circular part, we can conclude that the total distance covered in this time is given as circumference of the circle.

which is expressed as

$Distance=2\pi R$

To determine the speed, we use the equation

$speed=(distnce)/(time)\n Speed=(2\pi R)/(time)\n speed=(2\pi*5 )/(4)\n Speed=7.85m/s$

The acceleration as required is expressed as

$a=(v^(2))/(r)\n a=(7.85^(2))/(5)\n a=12.3m/s^(2)$

if the speed increase and it takes 3secs to complete one circle, the speed is

$speed=(distnce)/(time)\n Speed=(2\pi R)/(time)\n speed=(2\pi*5 )/(3)\n Speed=10.47m/s$

and the acceleration becomes

$a=(v^(2))/(r)\n a=(10.47^(2))/(5)\n a=21.93m/s^(2)$

Answer 2

Answer:

The acceleration of the passengers in the vertical circle carnival ride is 19.6 m/s^2. When the time taken to complete one circle is 3.0 s, the new acceleration is 26.13 m/s^2.

The acceleration of the passengers can be determined using the centripetal acceleration formula, which is given by a = v^2 / r.

In this case, the velocity v can be found by dividing the circumference of the circle (2πr) by the time taken to complete one circle (T). The radius r is given as 5.0 m. Plugging in the values, we have:

a = (v^2) / r = ((2πr / T)^2) / r = (4π^2r) / T^2 = (4π^2 * 5.0) / 16.0 = 19.6 m/s^2

To find the new acceleration when the time taken to complete one circle is 3.0 s, we can use the proportional reasoning to determine the relationship between the two accelerations. Since the time is inversely proportional to the acceleration, when T is 3.0 s, the new acceleration arad can be found using the equation:

arad / 19.6 = 4.0 / 3.0

Simplifying the equation, arad = (19.6 * 4.0) / 3.0 = 26.13 m/s^2

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Air contained in a rigid, insulated tank fitted with a paddle wheel, initially at 300 K, 2 bar, and a volume of 2 m3 , is stirred until its temperature is 500 K. Assuming the ideal gas model for the air, and ignoring kinetic and potential energy, determine (a) the final pressure, in bar, (b) the work, in kJ, and (c) the amount of entropy produced, i

Answers

Final answer:

To find the final pressure, use the ideal gas law equation PV = nRT, where P is the initial pressure, V is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the initial temperature. Rearrange the equation and plug in the given values to find that the final pressure is 3.33 bar.

Explanation:

To find the final pressure, we can use the ideal gas law equation: PV = nRT, where P is the initial pressure, V is the initial volume, n is the number of moles of gas, R is the gas constant, and T is the initial temperature.

Since the volume and the amount of air are constant, we can rearrange the equation to solve for the final pressure:

P2 = P1 * (T2 / T1),

where P2 is the final pressure, T2 is the final temperature, and T1 is the initial temperature.

By plugging in the values from the problem, we can find that the final pressure is 3.33 bar.

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An indestructible bullet 2.00cm long is fired straight through a board that is 10.0cm thick. The bullet strikes the board with a speed of 470 m/s and emerges with a speed of 270 m/s. (To simplify, assume that the bullet accelerates only while the front tip is in contact with the wood.) a). What is the average acceleration of the bullet through the board? ________m/s^2b). What is the total time that the bullet is in contact with the board? (Enter the total time for the bullet to completely emerge from the board.) _________s
c.) What thickness of board (calculated 0.1 cm) would it take to stop the bullet, assuming that the acceleration through all boards is the same? ________cm

Answers

Answer:

a) $a=-7.4* 10^(-5)\ m/s^2$

b) $t=0.27* 10^(-3)\ s$

c)s=14.92 cm

Explanation:

Given that

u= 470 m/s

v = 270 m/s

s= 10 cm

We know that

$v^2=u^2+2as$

$270^2=470^2+2* a* 0.1$

$a=-7.4* 10^(-5)\ m/s^2$

v= u + a t

$270=470-7.4* 10^(-5)* t$

$t=0.27* 10^(-3)\ s$

To stop the bullet it means that the final velocity will be zero.

$v^2=u^2+2as$

$0^2=470^2-2* 7.4* 10^(-5) * s$

s=14.92 cm

A steel ball is dropped onto a thick piece of foam. The ball is released 2.5 meters above the foam. The foam compresses 3.0 cm as the ball comes to rest. What is the magnitude of the ball's acceleration as it comes to rest on the foam

Answers

Answer:

the magnitude of the ball's acceleration as it comes to rest on the foam is 817.5 m/s²

Explanation:

Given the data in the question;

initial velocity; u = 0 m/s

height; h = 2.5 m

we find the velocity of the ball just before it touches the foam.

using the equation of motion;

v² = u² + 2gh

we know that acceleration due gravity g = 9.81 m/s²

so we substitute

v² = ( 0 )² + ( 2 × 9.81 × 2.5 )

v² = 49.05

v = √49.05

v = 7.00357 m/s

Now as the ball touches the foam

final velocity v₀ = 0 m/s

compresses S = 3 cm = 0.03 m

v₀² = v² + 2as

we substitute

( 0 )² = 49.05 + 0.06a

0.06a = -49.05

a = -49.05 / 0.06

a = -817.5 m/s²

Therefore, the magnitude of the ball's acceleration as it comes to rest on the foam is 817.5 m/s²

Give a quantitative definition of being in contact.

Answers

Two things are said to be in contact if the smallest distance between a point in one of them and a point in the other one is zero.

A thin Nichrome wire connected to an ammeter surrounds a region of time-varying magnetic flux, and the ammeter reads 13 amperes. If instead of a single wire we use a coil of thin Nichrome wire containing 23 turns, what does the ammeter read?

Answers

Answer:

The current would be same in both situation.

Explanation:

Given that,

Current I = 13 A

Number of turns = 23

We need to calculate the induced emf

Using formula of induced emf is

$\epsilon=NA(dB)/(dt)$

For N = 1

$\epsilon=A(dB)/(dt)$

We need to calculate the current

Using formula of current

$i=(\epsilon)/(R)$

Put the value of emf

$i=(A(dB)/(dt))/(R)$

Now, if the number of turn is 22 , then induced emf would be

$\epsilon'=NA(dB)/(dt)$

Then the current would be

$i'=(\epsilon')/(NR)$

$i'=(NA(dB)/(dt))/(NR)$

$i'=(A(dB)/(dt))/(R)$

$i'=i$

Hence, The current would be same in both situation.

PLEASE HELP QUICKLY!A volleyball player jumps to hit a ball horizontally at 7.0 m/s straight on. If the
height at which the ball was hit is 3.0 m tall, how far did the ball go horizontally
before it hit the ground?
5.5 m
3.6 m
O 4.3 m
4.2 m

Answers

Answer:

5.5 is the correct answer

please keeps as Brainly list

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