MATHEMATICS COLLEGE

A Popsicle store at the beach is comparing their monthly revenue with the sunglasses store next door. The shop owners find that their monthly revenue is positive correlated. This means that eating Popsicles causes people to buy sunglasses.True or False

Answers

Answer 1

Answer:

Answer:

False

Step-by-step explanation:

Correlation is not causation.

It may mean that eating popsicles and buying sunglasses have a common cause: sunny days.

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People tend to evaluate the quality of their lives relative to others around them (Frieswijk et al., 2004). In one study, researchers conducted interviews with n = 9 frail elderly people. During the interview, each person was compared with a fictitious person who was worse off than the elderly person. The scores below are the measures from a life-satisfaction scale for the elderly sample. Assume that the average score on this scale in the population is u = 20. Are the data sufficient to conclude that the elderly people in this sample are either significantly more or less satisfied than others in the general population? The life-satisfaction scores for the sample are 18, 23, 24, 22, 19, 27, 23, 26, 25. a. Which kind of t-test should you use? b. How many tails should the test have? Circle a word or phrase in the problem that told you this. c. State the null and alternative hypotheses in statistical notation: d. Determine the critical t using an alpha = .05. Sketch the null distribution, note the location of the critical t, and shade the critical region. e. Calculate the t-statistic and plot it on the sketch you drew above. f. Make a decision (either reject the null or fail to reject it)

Answers

Answer:

Step-by-step explanation:

Hello!

Research.

n=9 frail elderly were interview and compared to a fictitious person who was worse off then the interviewee, a life-satisfaction score was determined for each person.

18, 23, 24, 22, 19, 27, 23, 26, 25

Assuming that the population average score is μ= 20, the researchers think that the elderly in the sample are more or less satisfied than others in the general population.

a. You have the information of one sample, assuming this sample has a normal distribution and each elderly interviewed is independent, then the t-test of choice is a one-sample t-test.

b. and c. If you say that the elderly are "more or less" satisfied than the others, this means that they are either as satisfied as to the general population or not satisfied as to the general population. Symbolically:

H₀: μ = 20

H₁: μ ≠ 20

This is a two-tailed test, meaning, you will have two critical regions.

α: 0.05

Left critical value: $t_(n-1;/\alpha 2) = t_(8; 0.025)= -2.306$

Right critical value: $t_(n-1;1-\alpha /2) = t_(8;0.975) = 2.306$

$t_(H_0)= (X[bar]-Mu)/((S)/(√(n) ) ) ~t_(n-1)$

X[bar]= 23

S= 3

$t_(H_0)= (23-20)/((3)/(√(9) ) )= 3$

Considering that the calculated t-value is greater than the right critical value, the decision is to reject the null hypothesis, so using a significance level of 5% you can conclude that the average life-satisfaction score of the elderly is different than 20.

I hope it helps!

Solve for x hereee
Plsss fast !

Answers

$\sf{ x=6}$

Step-by-step explanation:

$4(x+4)+2x=52\n\n4x+16+2x=52\n\n6x+16=52\n\n6x=52-16\n\n6x=36\n\nx=(36)/(6)\n\n\bold x=6$

Verification:-

$4(x+4)+2x=52\n\n4(6+4)+2(6)=52\n\n4(10)+12=52\n\n40+12=52\n\n\tt 52=52$

Hence verified!!

Find the center of this circle by completing the square. x^2+y^2-6x+8y+10=0
Show work

Answers

Answer:

Center: (3, - 4)

Step-by-step explanation:

We can start to solve this problem by converting this equation into standard form. In other words, by completing the square --- (1)

Subtract " 10 " from either side of the equation x² + y² - 6x + 8y + 10 = 0

x² + y² - 6x + 8y = - 10

Step 1: Complete the square for the expression " x² - 6x "

Using the quadratic equation ax² + bx + c we know that a = 1, b = - 6, c = 0. Assume that d = b / 2a. We have...

d = - 6 / 2(1) = - 6 / 2 = - 3

Now let's assume that e = c - (b²) / 4a...

e = 0 - (-6)² / 4(1) = 0 - 36 / 4 = 0 - 9 = 9 (Substitute values d and e)

(x - 3)² - 9

Step 2: Respectively we can complete the square for the remaining expression " y² + 8y "

Here a = 1, b = 8, c = 0

d = 8 / 2(1) = 8 / 2 = 4

e = 0 - (8)² / 4(1) = 0 - 64 / 4 = 0 - 16 = - 16 (Substitute values)

(y + 4)² - 16

This leaves us with the expression " (x - 3)² - 9 + (y + 4)² - 16 = - 10. " If we simplify this a bit further it leaves us with the following circle equation. Using this we can identify the center of the circle as well --- (2)

$\mathrm{Standard}\:\mathrm{Circle}\:\mathrm{Equation} : (x - 3)^2 + (y +4)^2 = 15,\n\mathrm{General}\:\mathrm{Form} : (x - h)^2 + (y +k)^2 = r^2,\n\mathrm{Properties} : \mathrm{Center} = (3, - 4), \mathrm{Radius} = √(15)$

As you can see our center here is (3, - 4)

Give two examples of addition of two mixed numbers with different denominators
SHOW ALL STEPS

Answers

Answer:

First Example: 3 1/2 + 4 3/4, Second Example: 6 3/8 + 7 9/15

Extra Example: 8 4/20 + 3 5/10

Step-by-step explanation:

First Example:

1/2 + 3/4

1/2 is equal to 2/4 so it is now compatible to be added to 3/4.

2/4 + 3/4

= 5/4

Now for the mixed numbers since its 3 and 4, 3 + 4 = 7.

Final answer is 7 5/4.

Second Example:

3/8 + 9/15

9/15 can be reduced to 3/5

Now the equation is 3/8 + 3/5

= 15/40 + 24/40 is an equivalent equation

15/40 + 24/40

= 39/40

Now for the mixed numbers since its 6 and 7, 6 + 7 = 13

Final answer is 13 39/40.

I am going to include one last example just in case you need one:

Third Example:

4/20 + 5/10

We can reduce these to

1/5 + 1/2

= 2/10 + 5/10 is the equivalent equation

2/10 + 5/10

= 7/10

Now for the mixed numbers since its 8 and 3, 8 + 3 = 11.

Final answer is 11 7/10.

I Hope this helps!

A circle is divided into 6 equal parts. What is the angle measure of 1 part?

Answers

The angle measure of one part will be 60.

360/6 = 60

That is because the circle it divided into 6 equal parts and the whole circle is 360.

Hope this helps :)

A reservation service employs six information operators who receive requests for information independently of one another, each according to a Poisson process with rate ???? = 2 per minute. a. What is the probability that during a given 1 min period, the first operator receives no requests? (Round your answer to three decimal places.) b. What is the probability that during a given 1 min period, exactly three of the six operators receive no requests? (Round your answer to five decimal places.)

Answers

Answer:

a) 0.135 = 13.5% probability that during a given 1 min period, the first operator receives no requests.

b) 0.03185 = 3.185% probability that during a given 1 min period, exactly three of the six operators receive no requests

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

In which $C_(n,x)$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_(n,x) = (n!)/(x!(n-x)!)$

And p is the probability of X happening.

Poisson process with rate 2 per minute

This means that $\mu = 2$

a. What is the probability that during a given 1 min period, the first operator receives no requests?

Single operator, so we use the Poisson distribution.

This is P(X = 0).

$P(X = x) = (e^(-\mu)*\mu^(x))/((x)!)$

$P(X = 0) = (e^(-2)*2^(0))/((0)!) = 0.135$

0.135 = 13.5% probability that during a given 1 min period, the first operator receives no requests.

b. What is the probability that during a given 1 min period, exactly three of the six operators receive no requests?

6 operators, so we use the binomial distribution with $n = 6$

Each operator has a 13.5% probability of receiving no requests during a minute, so $p = 0.135$

This is P(X = 3).

$P(X = x) = C_(n,x).p^(x).(1-p)^(n-x)$

$P(X = 3) = C_(6,3).(0.135)^(3).(0.865)^(3) = 0.03185$

0.03185 = 3.185% probability that during a given 1 min period, exactly three of the six operators receive no requests

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