lucose, a major energy-yielding nutrient, is present in bacterial cells at a concentration of approximately 0.200 mM. i) What is the concentration of glucose in the E. coli cell in mg/mL?

Answer:

The answer is 20

Explanation:

The limiting reagent and the number of S'mores produced for each of the reactions is given below:

Reaction 1. The limiting reagent is Cp; 1.6 S'mores are produced.

Reaction 2. The limiting reagent is M;2 S'mores are produced.

Reaction 3. The limiting reagent is Gc; 2.5 S'mores are produced.

Reaction 4. The limiting reagent is M;1 S'more is produced.

Stoichoimetry

• Stoichiometry is the process of measuring quantitatively the mass and quantity relationships among reactants and products in a given reaction.

The equation of the reaction shows the stoichiometry between reactants and products.

For the given reaction, the equation of reaction is as follows:

1M + 2Gc + 3Cp ----> 1Gc2MCp3

where:

• Gc = Graham Cracker
• M = Marshmallow
• Cp = Chocolate pieces
• S’more = Gc2MCp3

From the equation of reaction:

• 1 marshmallow, 2 Graham cracker and 3 chocolate pieces are required to make 1 S'more

Calculating the number of S'mores and the limiting reactant of the given reaction

The stoichiometric equation is: 2Gc + 1M + 3Cp ----> 1Gc2MCp3

The ratio of Gc to M to Cp is 2 : 1 : 3

Reaction 1. 4 Gc + 2M + 5 Cp

The ratio of Gc to M to Cp in the reaction above is 2 : 1 : 2.5

• Therefore the limiting reagent is Cp

3 Cp makes 1 S'more

5  Cp will make 5 * 1/3 S'more = 1.6 S'mores

• Therefore, 1.6 S'mores are produced.

Reaction 2. 6 Gc + 2M + 9 Cp

The ratio of Gc to M to Cp in the reaction above is 3 : 1 : 4.5

• Therefore the limiting reagent is M

1 M makes 1 S'more

2  Cp will make 2 * 1/1 S'more = 2 S'mores

• Therefore, 2 S'mores are produced.

Reaction 3. 5 Gc + 3M + 9 Cp

The ratio of Gc to M to Cp in the reaction above is 1.6 : 1 : 3

• Therefore the limiting reagent is Gc

2 Gc makes 1 S'more

5 Gc will make 5 * 1/2 S'more = 2.5 S'mores

• Therefore, 2.5 S'mores are produced.

Reaction 4. 7 Gc + 1M + 6 Cp

The ratio of Gc to M to Cp in the reaction above is 7 : 1 : 6

Therefore the limiting reagent is M

1 M makes 1 S'more

• Therefore, 1 S'more is produced.

The limiting reagent and the number of S'mores produced for each of the reactions is given below:

1. The limiting reagent is Cp; 1.6 S'mores are produced.

2. The limiting reagent is M;2 S'mores are produced.

3. The limiting reagent is Gc; 2.5 S'mores are produced.

4. The limiting reagent is M;1 S'more is produced.

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Answer:

The type of RNA that contains the information for making a protein is called messenger RNA (mRNA) because it carries the information, or message, from the DNA out of the nucleus into the cytoplasm.

Answer:

Messenger RNA (mRNA)

Explanation:

Messenger RNA (mRNA), Molecules  in cells that carries codes from the DNA in the nucleus to the sites of protein synthesis in the cytoplasm (the ribosomes)...

Hope This helps if not Then im Sorry XD

The best example of natural plasma is the ionosphere of the atmosphere including solar corona and lightning including auroras cloud.

What is natural plasma?

the heated or hot  matter that is so hot that the electrons are thrown away from the atoms and forms the ionized gas. Comprises over 99% of the visible universe.

Lightning strikes create plasma by doing a stricking of electricity. Mostly the Sun, and some stars, are in a plasma state. Certain regions of Earth's atmosphere contain some plasma created primarily by ultraviolet radiation from the Sun.

One reason plasma is not so common is because this needs high temperatures required to keep gas in the plasma state. At average temperatures on Earth, there just isn't enough energy for atoms to remain ionized.

However, at thousands to millions of degrees Kelvin, these energies are available, and plasmas dominate

Therefore, aurora clouds  are natural plasma.

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Answer:

aurorus

Explanation:

Answer: 22.8atm

Explanation:

T1 = —13°C = —13 +273 = 260K

T2 = 24°C = 24 +273 = 297K

V1 = V

V2 = 35% of V= 0.35V

P1 = 7atm

P2 =?

P1V1/T1 = P2V2 /T2

(7 x V)/260 = (P2 x 0.35V)/297

P2x0.35Vx260 = 7V x 297

P2 x 91V = 2079V

P2 = 2079V / 91V

P2 = 22.8atm

Answer:

the equilibrium partial pressure of BrCl is pBC = 784.52 torr

Explanation:

Since

Br₂(g) + Cl₂(g) ⇌ 2BrCl(g) , Kp=1.112 at 150 K

denoting BC as BrCl , B as Br₂ , C as Cl₂, p as partial pressure , then

Kp = pBC²/[pB*pC]

solving for pBC

pBC = √(Kp*pB*pC)

replacing values

pBC = √(Kp*pB*pC) = √(1.112*751 torr*737 torr) = 784.52 torr

pBC = 784.52 torr

then the equilibrium partial pressure of BrCl is pBC = 784.52 torr

Final answer:

To calculate the equilibrium partial pressure of BrCl, use the equilibrium constant expression and substitute the given partial pressures of Br2 and Cl2. The equilibrium partial pressure of BrCl is approximately 0.0375 atm.

Explanation:

To calculate the equilibrium partial pressure of BrCl, we need to use the equilibrium constant expression:

Kp = ([BrCl]^2) / ([Br2] * [Cl2])

Given that the equilibrium partial pressures of Br2 and Cl2 are 0.450 atm and 0.115 atm, respectively, we can substitute these values into the expression:

1.112 = ([BrCl]^2) / (0.450 * 0.115)

Simplifying the expression, we find that the equilibrium partial pressure of BrCl is approximately 0.0375 atm.

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