Answer:
3x^2 + 3xz + 2y^2 - 2yz - xy
Step-by-step explanation:
(1) multiply it to get
3x^2 - 3xy + 3xz and 2yx + 2y^2 - 2yz
add similar variables (-3xy + 2yx)
( the order of the variables doesn't matter xy or yx is the same)
we get -xy
and then after that simplifying we get 3x^2 + 3xz + 2y^2 - 2yz - xy
Answer:
Step-by-step explanation:
hello :
3x(x-y+z) + 2y (x+y-z) = 3x²-3xy+3xz +2yx+2y²-2yz
3x(x-y+z) + 2y (x+y-z) = 3x² -xy+3xz -2yz+2y²
a 21
b-7
c-21
d-42
the carousel costs 5 tokens. The inequality
7x + 5y = 50 represents the possible ways
Marcus could use his tokens on the two rides.
Is the ordered pair (6, 3) a solution for the
problem situation?
Answer:
The ordered pair (6,3) can not be a solution for the problem situation.
Step-by-step explanation:
Marcus has total 50 tokens to spend at the carnival.
Now, given that the Ferris wheel costs 7 tokens and the carousel costs 5 tokens.
So, if Marcus play the Ferris wheel for x times and the carousel for y times, the total expenditure will be given by
7x + 5y = 50 ............ (1)
Now, the ordered pair (6,3) i.e. x = 6 and y = 3 does not satisfy the above relation equation (1).
So, the ordered pair (6,3) can not be a solution for the problem situation. (Answer)
Answer:
58
Step-by-step explanation:
52+24=76
180-76=104
104+18=122
180-122=58
V=58