A sample of compressed methane has a volume of 648 mL at a pressure of 503 kPa. To what pressure would themethane have to be compressed in order to have a volume of 216 mL?
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In order to have a volume of 216 ml, the methane have to be compressed at a pressure of 1509 kPa.
Explanation:
This problem is solved by using Boyle's law which states that at constant temperature pressure of a gas is inversely proportional to its volume. It describes how the pressure of a gas increases with a decrease in the volume of a container. The formula is given as,
P1 V1 = P2 V2
where P1 and V1 are first pressure and volume,
P2 and V2 are second pressure and volume.
Given P1 = 503 kPa, V1 = 648 ml, and V2 = 216 ml
P2 = (P1 V1 ) / V2 = (503
648) / 216
P2 = 1509 kPa.
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