How would you characterize the flame test with respect to its sensitivity

Answers

Answer 1

Answer:

Answer:

Flame test is the procedure to find out the metal ions in the ionic compounds. By observing the color of flame we find out the presence of certain metallic ion. For example if we take the test of copper halide, the flame will become of the bluish green color due to the copper ion. You can perform the test with the common salt. Upon putting it on the flame, the color of flame will become yellow due to the presence of sodium ion. Similarly aluminium shows blue and calcium brick red etc.

Explanation:

Answer 2

Answer:

Final answer:

The flame test, used in chemistry to identify certain substances through the color of their flame, has limited sensitivity, as some elements produce similar flame colors and multiple elements in a sample can complicate interpretation. Still, it remains a valuable tool in qualitative analysis. Other assessments, such as the NFPA 704 Hazard Identification System, can help understand the reactiveness and flammability of substances.

Explanation:

Characterizing the flame test with respect to its sensitivity involves understanding the minimal amount of a compound that the test can detect. Just like our senses have an absolute threshold for detection, so does the flame test. It can identify the presence of various elements in a compound based on the color of the flame. For example, sodium and its compounds impart a bright yellow color to a flame whereas lithium creates a bright, crimson color.

Despite its usefulness, the flame test may not be the most sensitive method for substance identification. Some elements may produce similar flame colors, making it difficult to distinguish between them. Moreover, the presence of multiple elements in a sample can also complicate the interpretation of flame test results. Therefore, while the flame test is a valuable tool in qualitative analysis, its sensitivity is somewhat limited.

According to the National Fire Protection Agency (NFPA) 704 Hazard Identification System, each substance has its own degree of hazard that ranges from 0 to 4. This information is critical in understanding the reactivity and flammability of substances, and is another aspect to consider when characterizing the sensitivity of the flame test.

Learn more about Flame Test Sensitivity here:

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A unit of power equal to 746 watts is a(n)__

Answers

1 Horsepower.
A Horsepower = 746 watts

A horizontal 20.-newton force is applied to a 5.0-kilogram box to push it across a rough,horizontal floor at a constant velocity of 3.0 meters per second to the right.

Calculate the coefficient of kinetic friction between the box and the floor. [Show all work, including
the equation and substitution with units]

Answers

The formula to work out the coefficient of dynamic (kinetic) friction is F=uR where F is the force applied, u is the coefficient of dynamic friction, and R is the reaction force. This is based on the principle the object is moving at a constant velocity which is the case in this question.

Rearranging this we get u=F/R
Substituting in the values we get u=20/50=2/5=0.4

Therefore the coefficient of kinetic friction between the box and the floor is 0.4

The coefficient of kinetic friction between the box and the floor will be $\boxed{0.4}$ .

Further Explanation:

Given:

The mass of the box is $5\,{\text{kg}}$ .

The force applied on the box is $20\,{\text{N}}$ .

The constant velocity at which the box moves is $3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}$ .

Concept:

The box is pushed on the rough floor and due to this; the box will experience a friction force acting in the direction opposite to the motion of the box.

Since the box moves with a constant velocity of $3\,{{\text{m}}\mathord{\left/{\vphantom{{\text{m}}{\text{s}}}}\right.\kern-\nulldelimiterspace}{\text{s}}}$ , the acceleration of the box will be considered as zero.

From Newton’s second law of motion, as the acceleration of the box is zero, the net force acting on the box is zero.

$\boxed{{F_(net)}=m* a}$

The free-body diagram of the box moving on the rough floor is as shown in figure attached below.

From the above explanation, in order to make the net force zero, the friction acting on the box should be equal to the force applied on the box.

${F_(friction)}={F_(applied)}$

The friction force acting on the bxlock is:

$\begin{aligned}{F_(friction)}&=\mu N\n&=\mu mg\n\end{aligned}$

Substitute the value of friction force in the above expression.

$\begin{aligned}\mu mg&={F_(applied)}\n\mu\left({5*10}\right)&=20\n\mu &=\frac{{20}}{{50}}\n&=0.4\n\end{aligned}$

Thus, the coefficient of kinetic friction between the box and the floor will be $\boxed{0.4}$ .

Learn More:

1. A 30.0-kg box is being pulled across a carpeted floor by a horizontal force of 230 N brainly.com/question/7031524

2. Choose the 200 kg refrigerator. Set the applied force to 400 n (to the right). Be sure friction is turned off brainly.com/question/4033012

3. Which of the following is not a component of a lever brainly.com/question/1073452

Answer Details:

Grade: High School

Subject: Physics

Chapter: Friction

Keywords:

Horizontal 20N force, 5 kg box, push, a rough horizontal floor, constant velocity, friction force, coefficient of kinetic friction, box and the floor.

A large sphere has a mass of 175 kg and is suspended by a chain from the ceiling. The mass of the chain is 12.0 kg. What is the tension in the chain?1830, N1610, N1720, N1940 N.

Answers

Each point in the chain supports the weight of all the mass below it.

At the bottom end of the chain, the weight is (175 x 9.8) = 1,715 N .
At the top of the chain, the weight is (175 + 12) x (9.8) = 1,833 N .

The tension in the chain varies linearly from 1,715N at the bottom
to 1,833N at the top.

Which of the following is not an example of work?A. raising a barbell over your head

B. picking up a box off the floor

C. holding a tray in the cafeteria line

D. pushing a box across the floor

Answers

The following which is not an example of work is C. holding a tray in the cafeteria line because if force displaces an object it should work. I think it's clear and I am pretty sure this answer will help you.

A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m 27, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when the rider slams on the brakes. The bike skids 41.5 m 41.5m41, point, 5, start text, m, end text with constant acceleration before it comes to a stop. What was the acceleration of the motorbike as it came to a stop?

Answers

Answer:

Explanation:

Initial velocity , u = 27 m/s

displacement before stop, s = 41.5 m .

final velocity, v = 0

acceleration a = ?

v² = u² + 2 a s

0 = 27² + 2 x a x 41.5

a = - 27² / 2 x 41.5

= - 8.78 m /s

1. Read each description below. Choose the force diagram (free-body diagram) that best represents the description. The forces are acting on the object in red type. You may neglect the effects of air resistance. A. Mindy's Christmas tree ornament hangs motionless on a tree.
B. Corey's Christmas tree ornament is falling to the floor.
C. A ball thrown by Ginger is moving upward through the air.
D. A ball dropped by Melissa is falling downward toward the floor.
E. Matt's book is motionless on a table.
F. A ball that was thrown upward by Yvonne is at the top of its path.

For each statement, please choose a diagram representing the force on the object. (Diagrams are in the attachment)

Answers

A. Mindy's Christmas tree ornament hangs motionless on a tree. --- Diagram C
B. Corey's Christmas tree ornament is falling to the floor. --- Diagram A
C. A ball thrown by Ginger is moving upward through the air. --- Diagram B
D. A ball dropped by Melissa is falling downward toward the floor. --- Diagram A
E. Matt's book is motionless on a table. --- Diagram C
F. A ball that was thrown upward by Yvonne is at the top of its path --- Diagram A.

Final answer:

Free-body diagrams are tools to visualize external forces on an object, drawn as a point. Each scenario given (hanging ornament, falling ornament, moving and dropped balls, book on a table, and ball at top of its path) will have a unique diagram with forces like gravity, tension, and normal force labeled as vectors, and x/y components shown if necessary.

Explanation:

In physics, a free-body diagram is a graphical representation used to visualize the forces acting on an object. To correctly create a free-body diagram, follow these steps:

Draw the object as a point, especially when considering it as a particle.
Label all the external forces acting on the object with vector arrows.
Resolve each force into its x and y components if necessary for analysis.
Create separate diagrams for each object if multiple objects are involved.

Each scenario provided in the question will have a different free-body diagram:

Mindy's Christmas tree ornament: It's stationary, with two forces in balance: gravitational force (weight) pulling down and the tension in the string pulling up.
Corey's Christmas tree ornament: Only one force, gravitational force, is acting on it as it falls.
Ginger's ball moving upward: Two forces here - gravitational force pulling down and the initial upward force while it moves up.
Melissa's dropped ball: Similar to B, only gravitational force acts on it.
Matt's book on a table: Gravitational force pulls it down while the normal force from the table supports it from below.
Yvonne's ball at the top of its path: Though motionless at this instant, the only force acting on it is gravity.

Note, while drawing a free-body diagram, do not include net forces or internal forces.

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