What will be the theoretical yield of tungsten(is) ,W, if 45.0 g of WO3 combines as completely as possible with 1.50 g of H2

Answers

Answer 1
Answer:

Answer:

35.6 g of W, is the theoretical yield

Explanation:

This is the reaction

WO₃  +  3H₂  →   3H₂O  +  W

Let's determine the limiting reactant:

Mass / molar mass = moles

45 g / 231.84 g/mol = 0.194 moles

1.50 g / 2 g/mol = 0.75 moles

Ratio is 1:3. 1 mol of tungsten(VI) oxide needs 3 moles of hydrogen to react.

Let's make rules of three:

1 mol of tungsten(VI) oxide needs 3 moles of H₂

Then 0.194 moles of tungsten(VI) oxide would need (0.194  .3) /1 = 0.582 moles (I have 0.75 moles of H₂, so the H₂ is my excess.. Then, the limiting is the tungsten(VI) oxide)

3 moles of H₂ need 1 mol of WO₃ to react

0.75 moles of H₂ would need (0.75 . 1)/3 = 0.25 moles

It's ok. I do not have enough WO₃.

Finally, the ratio is 1:1 (WO₃ - W), so 0.194 moles of WO₃ will produce the same amount of W.

Let's convert the moles to mass (molar mass  . mol)

0.194 mol . 183.84 g/mol = 35.6 g


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Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of potassium sulfide and chromium(II) nitrate are combined. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed leave it blank. 2Cr^3+ + 3S^2- (aq) + + rightarrow Cr_2S_4 (s) +

Answers

Answer:

S²⁻(aq) + Cr²⁺(aq) ⇄ CrS(s)

Explanation:

The molecular equation includes all the species in the molecular form. Usually, it is useful to write this first to balance the equation. This is a double displacement reaction.

K₂S(aq) + Cr(NO₃)₂(aq) ⇄ 2 KNO₃(aq) + CrS(s)

The full ionic equation includes all ions and the species that no dot dissociate in water.

2 K⁺(aq) + S²⁻(aq) + Cr²⁺(aq) + 2 NO₃⁻(aq) ⇄ 2 K⁺(aq) + 2 NO₃⁻(aq) + CrS(s)

The net ionic equation includes only those ions that participate in the reaction and the species that do not dissociate in water.

S²⁻(aq) + Cr²⁺(aq) ⇄ CrS(s)

The net ionic equation for the precipitation reaction is: Cr+ + 3S → CrS(s)

The net ionic equation for the precipitation reaction between potassium sulfide and chromium(II) nitrate can be written as:

Cr + 3SCrS(s)

In this reaction, the chromium(II) ions (Cr) react with the sulfide ions (S) to form chromium(II) sulfide (CrS) which precipitates as a solid.

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C6H6NCl On the basis of the molecular formula, 1H NMR data, and IR data provided, propose a consistent structure.H`NMR data: δ 300 (s, 2H), 6.57 (d, 2H), 7.05 (d, 2H)
IR data: 3400 (broad), 3250 (broad), 1590, 820 cm^(-1).

Draw your proposed structure below.

Answers

Answer:

Please refer to the attachment below.

Explanation:

Please refer to the attachment below for explanation.

A weather balloon has a volume of 200.0 L at a pressure of 760 mm Hg. As it rises, the pressure decreases to 282 mm Hg. What is the new volume of the balloon? (Assume constant temperature)

Answers

Answer:

The new volume of the balloon is 539 L

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide less times per unit time against them. This means that the pressure will be less because it represents the frequency of gas strikes against the walls. In this way, pressure and volume are related, determining Boyle's law that says:

"The volume occupied by a given gas mass at constant temperature is inversely proportional to the pressure"

Boyle's law is expressed mathematically as:

Pressure * Volume = constant

o P * V = k

Having an initial state 1 and an final state 2 will be fulfilled:

P1 * V1 = P2 * V2

So, in this case, you know:

  • P1= 760 mmHg
  • V1= 200 L
  • P2= 282 mmHg
  • V2= ?

Replacing:

760 mmHg*200 L= 282 mmHg*V2

Solving:

V2=(760 mmHg*200 L)/(282 mmHg)

V2=539 L

The new volume of the balloon is 539 L

Write the expression for the equilibrium constant Kp for the following reaction. Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH3 )2 as (P NH3)2. If either the numerator or denominator is 1, please enter 1 2 MoO3(s) ↔ 2 MoO2(s) + O2(g)

Answers

The expression  for the equilibrium constant Kp for the following reaction is  K_p = (po_2)

Equilibrium constant:

It refers to the ratio of the concentration of products to the concentration of reactants where each raised to the power of their stoichiometric ratios. It is expressed as K.

Since the given expression is

MoO3(s) ↔ 2 MoO2(s) + O2(g)

So, the above expression should be considered for constant kp

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Answer: K_p={(p_(O_2))}

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as K

K_p is the constant of a certain reaction at equilibrium for gaseous reactants and products.

For the given chemical reaction:

MoO_3(s)\rightleftharpoons 2MoO_2(s)+O_2(g)

The expression of  for above equation follows:

K_p={(p_(O_2))}

As solids do not exert pressure, MoO_3 and MoO_2  are not involved.

Identify the molecule with the strongest intermolecular force.C6H6
OF2
CHCl3
H2O

Answers

Answer:

C6H6 has the strongest intermolecular force

i think

Answer:

H2O

Explanation:

Because it is a hydrogen bond which is said to be the strongest bond between the H and a N,O, or F combination

How to prepare ethanoic acid from ethane

Answers

anonymous
anonymous 5 years ago
First you chlorinate it in presence of light.
C2H6 + Cl2 ---hv -> C2H5Cl + HCl
Then you add aqeuos KOH to get C2H5OH
C2H5Cl+KOH-> C2H5OH+ KCl.
Then you add KMnO4 to get the rquired compound.
C2H5OH ----KMnO4 ---> CH3COOH.
C2h6 + O2 ----> CH3CooH