PHYSICS HIGH SCHOOL

A drag racer starts her car from rest and accelerates at 11.9 m/s2 for the entire distance of 400 m. What is the speed of the race car at the end of the run?

Answers

Answer 1
Answer:

Speed of the race car at the end of the run is 97.57 m/s

Explanation:

We have equation of motion v² = u² + 2as

Initial velocity, u = 0 m/s  

Acceleration, a = 11.9 m/s²  

Final velocity, v = ?

Displacement,s = 400 m

Substituting  

v² = u² + 2as

v² = 0² + 2 x 11.9 x 400

v = 97.57 m /s

Speed of the race car at the end of the run is 97.57 m/s

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Answers

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Two strings of equal length are stretched out with equal tension. The second string is four times as massive as the first string. If a wave travels down the first string with velocity v , how fast does a wave travel down the second string?

Answers

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Sa ma ajute cineva va rog mult Ce cantitate de apă poate fi încălzită de la temperatura t 1 = 10 0 C la temperatura finală T 2 = 293, 15 K, dacă i se furnizează căldura de 41850 J ? Se dă căldura specifică a apei : c apă = 4185

Answers

Răspuns:

1000 kg

Explicaţie:

Date date

t1 = 10 ° C

t2 = 293,15K = până la grad = 293,15-273 = 20,15 ° C

= 20 ° C    aproximativ

Q = 418kJ = 418000J

c = 4180J / kg ° C

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Necesar:

Masa m în kg

Pasul doi:

Formulă:

Q = c * m * Δt

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m = Q / c * (t2-t1)

Calculati:

m = 418000/4180 * (20-10)

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