MATHEMATICS COLLEGE

A student who has created a linear model is disappointed to find that herR2 value is a very low 13%. a) Does this mean that a linear model is not appropriate? Explain. b) Does this model allow the student to make accurate predictions? Explain.

Answers

Answer 1

Answer:

Answer:

a) No it doesn't mean that linear model is inappropriate

b) No. The prediction using this model will not be accurate.

Step-by-step explanation:

For answering this part, firstly consider the concept of $R^(2)$

The $R^(2)$ also known as coefficient of determination is used to determine the amount of variability in dependent variable is explained by the linear model. Lower $R^(2)$ depicts that less variation of dependent is explained by the independent variable using the linear model. The linearity of model is determined by scatter plot. Thus, if the $R^(2)$ is lower, it doesn't mean that linear model is inappropriate.

The predictions made by the model having lower $R^(2)$ value are erroneous. The model is used for prediction if the linear model explains the larger portion of variability in dependent variation. If the predictions made from the model that have lower $R^(2)$ value then the predicted values will not be close to the actual value and thus residuals will not be minimum as residuals are the difference of actual and predicted values.

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Please explain as well 4x+3y=24 6x+5y=346x+5y=34 x= y=

09:30 to 17:00 minus 30 minutes
How many hours is that ?

Answers

Answer:

7 hours

Step-by-step explanation:

9 : 30 to 17:00 = 7 hours 30 minutes

Minus 30 minutes = 7 hours

Solve the inequality 1/3h≤7

Answers

Answer:

h ≤ 21

Step-by-step explanation:

Simply just divide both sides by 1/3 to isolate x and you should get your answer!

Answer:

h ≤ 21

Step-by-step explanation:

1/3h ≤ 7

Multiply 1/3 on both sides of the inequality.

1/3(1/3h) ≤ 1/3(7)

h ≤ 1/3(7)

Reciprocal 1/3.

h ≤ 7(3/1)

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consider a population of voters. suppose that that there are n=1000 voters in the population, 30% of whom favor jones. identify the event favors jones as a success s. it is evident that the probability of s on trial 1 is 0.30. consider the event b that s occurs on the second trial. then b can occur two ways: the first two trials are both successes or the first trial is a failure and the second is a success. show that p(b) = 0.3

Answers

Answer:

P(B)=0.30

Step-by-step explanation:

Out of 1000 Voters, 30% favor Jones.

Event S=Favors Jones on First Trial

Event B=S occurs on Second Trial

P(S)=0.30

P(S')=1-0.30=0.70

Event B could occur in two ways

The first two trials are a success
The first trial is a failure and the second trial is a success.

Therefore,

P(B)=P(SS)+P(S'S)

=(0.3X0.3)+(0.7X0.3)

=0.09+0.21

=0.3

Therefore, the probability of event B(that event S occurs on the second trial), P(B)=0.30.

15 1/2 as an integer

Answers

2 good luck on ur work :)

Find domain and range of y=x+3

Answers

Answer:

The domain is all real numbers and the range is all real numbers

Step-by-step explanation:

The distance travel on the x-axis, you will travel on the complete axis so the answer to the domain is all real numbers. For the range, the distance travel on the y-axis, you travel on the complete axis so the answer is all real numbers.

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