PHYSICS HIGH SCHOOL

A metal object is suspended from a spring scale. The scale reads 930 N when the object is suspended in air, and 731 N when the object is completely submerged in water. Find the volume of the object. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m3 .

Answers

Answer 1

Answer:

Answer:

The volume of the object = 0.0203 m³

Explanation:

From Archimedes principle,

Upthrust = lost in weight = amount of water displaced.

U = W₁ - W₂

Where U = upthrust, W₁ = Weight in air, W₂ = weight in water.

U = 930- 731

U = 199 N.

but mass of water displaced,

m = U/g where g = 9.8 m/s²

m = 199/9.8

m = 20.31 kg.

Recall,

Density = mass/volume.

Density of water = mass of water displaced/ volume of water displaced

D = m/V

V = m/D......................................... Equation 1

Where V = volume of water displaced, m = 20.31 kg, D = 1000 kg/m³

Substitute into equation 1

V = 20.31/1000

V = 0.0203 m³

the volume of water displaced = 0.0203 m³

Note: That when an object is immersed in water, the volume of water it displaced is equal to it's volume.

Hence, Volume of water displaced = volume of the object.

Hence the volume of the object = 0.0203 m³

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Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 100 N. What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?

Answers

We have that for the Question "What is the tension in the string connecting block 100 to block 99? What is the tension in the string connecting block 50 to block 51?"

it can be said that

The tension in the string connecting block 100 to block 99 = $1N$

The tension in the string connecting block 50 to block 51 = $50N$

From the question we are told

Each of 100 identical blocks sitting on a frictionless surface is connected to the next block by a massless string. The first block is pulled with a force of 100 N.

Assuming mass of each block is 1 kg

The equation for the force is given as

$F = ma\n\na = (F)/(m)\n\n = (100)/(100*1)\n\n = 1 m/s^2$

Now, between block 100 and 99,

$F = ma\n\nF = 1*1 \n\n= 1 N$

Now between block 50 and 51. There are 50 blocks behind 51 st block, so,

$m = 50 Kg\n\na = 1 m/s2 (assuming all blocks accelerate at same rate)\n\nF = 50 * 1\n\nF= 50 N$

For more information on this visit

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Answer:

The tension in the string connecting block 50 to block 51 is 50 N.

Explanation:

Given that,

Number of block = 100

Force = 100 N

let m be the mass of each block.

We need to calculate the net force acting on the 100th block

Using second law of newton

$F=ma$

$100=100m* a$

$ma=1\ N$

We need to calculate the tension in the string between blocks 99 and 100

Using formula of force

$F_(100-99)=ma$

$F_(100-99)=1$

We need to calculate the total number of masses attached to the string

Using formula for mass

$m'=(100-50)m$

$m'=50m$

We need to calculate the tension in the string connecting block 50 to block 51

Using formula of tension

$F_(50)=m'a$

Put the value into the formula

$F_(50)=50m* a$

$F_(50)=50*1$

$F_(50)=50\ N$

Hence, The tension in the string connecting block 50 to block 51 is 50 N.

A 0.15-kg ball is thrown into the air and rises to a height of 20.0 m. How much kinetic energy did the ball initially have?

Answers

IF the toss was straight upward, then the kinetic energy it got
from the toss is the gravitational potential energy it has at the top,
where it stops rising and starts falling.

Potential energy = (mass) x   (gravity) x (height)

   = (0.15 kg) x (9.8 m/s²) x (20 m)

   = 29.4 kg-m²/s² = 29.4 joules .

The conservation of energy says that energy in an isolated system remains constant, that it is not created nor destroyed but transforms from one form of energy to another.
So when the ball is thrown into the air, it has kinetic energy (KE). As it goes into the air, that kinetic energy transforms into gravitational potential energy (GPE). The higher it gets, the more GPE it has and therefore the less KE it has.
At the top, all of it is transformed into GPE and there is no KE.
But total energy at any point after the ball is thrown until it lands it has the same energy throughout.

Knowing this, you can set the beginning KE equal to the final GPE.
KE = GPE

Insert formula for GPE.

KE = mgh
KE = 0.15kg*9.8m/s^2*20.0m
KE = 29 J

The ball initially had 29 J of kinetic energy

what determines how atoms combine to form molecules? A. the arrangement of electrons B. the arrangement of nucleons C. the number of protons D. all of the above E. none of the above

Answers

The correct answer for the question that is being presented above is this one: "D. all of the above." The following determines how atoms combine to form molecules: the arrangement of electrons; the arrangement of nucleons; the number of protons

Three 9W -3 V bulbs is to be lighted by a suppy of 12 Volt.For this,a wire is to be connected in series with it.Th resistance of the wire should be:A) 1
B) 2
C) 3
D) 4

Answers

9W 3V bulb need current flow
I = P/V = 9/3 = 3A

connected serially, voltage drop on the wire will be = Vsupply - 3(Vbulb) = 12 - 3(3) = 3V.

resistance of the wire ,with I=3 and V=3, = V/I = 3/3 = 1 Ohm.

In order for a 3V bulb to dissipate 9W, the current through it must be 3A.
R = E/I = 3v/3A . The resistance of such a bulb is 1 ohm.

There are two correct answers to the question, since the question itself
is ambiguous and may be understood in two different ways (at least) ...
series and parallel.

If the three bulbs are in series and the mystery wire will be placed
in series with them, then . . . . .

-- The current everywhere in the series circuit is 3 A .
-- The resistance across the supply is R = E/I = 12v/3A = 4 ohms.
-- 3 of the total 4 ohms is in the bulbs.
-- The additional wire must provide the additional 1 ohm .

If the three bulbs are in parallel and the mystery wire will be placed
in series with them, then . . . . .

-- The three bulbs in parallel form an effective resistance of 1/3 ohm.
-- The voltage across the parallel section of the circuit is 3v.
-- The additional wire must drop 9 volts across itself.
-- The total current through the 3 branches of the parallel section,
as well as through the additional piece of wire in series with it, is 9 A.
-- The resistance of the wire must be R = E/I = 9v/9A = 1 ohm.

Verrry interesting !
Whether the bulbs are in series or in parallel,
the same 1-ohm piece of wire does the job.

Electromagnetic waves can transfer energy without which of the following?A. Medium.
B. Electric field.
C. Magnetic field.
D. Change in either a magnetic or an electric field.

Answers

The correct answer is A. Electromagnetic waves can transfer energy without a medium. Heat can be transferred through a vacuum only via radiation. Infrared waves are electromagnetic waves that does not require a medium to travel. Heat is transferred in a vacuum in the form of infrared waves.

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A tuning fork with a frequency of 512 Hz is used to tune a violin. When played together, beats are heard with a frequency of 4 Hz. The string on the violin is tightened and when played again, the beats have a frequency of 2 Hz. The original frequency of the violin was ______.

Answers

Answer:

508Hz

Explanation:

When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - this phenomenon is beat production

frequency is the number of oscillation a wave makes in one seconds.

f1-f2=beats

therefore f1=512Hz

f2=?

beats=4Hz

512Hz-f2=4Hz

f2=512-4

f2=508Hz

the original frequency of the violin is 508Hz

Final answer:

The original frequency of the violin was 508 Hz. This is based on the principle of beats, where the beat frequency is the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.

Explanation:

The original frequency of the violin string can be found using the principle of beats. The frequency of the beats is equal to the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.

Initially, the beat frequency was heard as 4 Hz. This indicates that the original frequency of the violin was either 512 Hz + 4 Hz = 516 Hz, or 512 Hz - 4 Hz = 508 Hz. However, when the violin string was tightened, the beat frequency decreased to 2 Hz, which means the frequency of the note it was producing increased.

Therefore, the violin must have initially been producing a note with lower frequency (508 Hz), and even after tightening the string, the note it now produces (510 Hz) remains lower than that of the tuning fork.

Learn more about Beat Frequency here:

brainly.com/question/29428851

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