PHYSICS HIGH SCHOOL

A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launches a horizontal shot that lands in the hole on the fly. The gallery erupts in cheers.

Answers

Answer 1

Answer:

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

$x=V_(o)cos \theta t$ ----------------------(1)

$y=y_(o)+V_(o) sin \theta t - (1)/(2)gt^(2)$ ---------(2)

$V=V_(o)-gt$ ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

$V_(o)$ is the golf ball's initial velocity

$\theta=0\°$ is the angle (it was a horizontal shot)

t is the time

y is the final height of the ball

$y_(o)$ is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

$t=\sqrt{(2 y_(o))/(g)}$

$t=\sqrt{(2 (12.5 m))/(9.8 m/s^(2))}$

$t=1.597$ s

Substituting (6) in (1):

$67.1 =V_(o) cos(0\°) 1.597$ -------------------(4)

Step 2: Finding $V_(o)$ :

From equation(4)

$67.1 =V_(o)(1) 1.597$

$V_0 = (6.71)/(1.597)$

$V_(o)=42.01$ m/s (8)

Substituting $V_(o)$ in (3):

$V=42.01 -(9.8)(1.597)$

v =42 .01 - 15.3566

V=26.359 m/s

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Why was the concern over global cooling replaced with a concern over global warming?

Answers

During 1970s, same observations were seen as what we have observed today pertaining to our climate. Journals were discussing that there would be warming because of greenhouse gases emissions. Also, it was observed between the years 1970 to 1990 that there was a steady surface temperature increase. Due to this, people are now fixated with global warming rather than on global cooling.

A bicyclist travels 60.0 in 3.5 hours. what is the cyclists average speed

Answers

Average speed = (distance)/(time to cover it). ..... (60)/(3.5 hours) = 17.143 per hour. ... (The 17.143 could be nanometers, inches, miles, light years etc. No unit is given in the question.)

60 miles in 3.5 hours. we need to divide to find how many miles he went in one hour.

so 60 divided by 3.5 is 17.1428571429

If you round he was going about 17 miles an hour

Explain why dogs pant during hot summer days using the concept of evaporation?

Answers

Dogs pant because they can't sweet out their heat so they pant it out (and drink water) to cool themselves down.

In what scenario will an athletes wrist be under tension

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Pulling a rope in tug-of-war

A coin rolls across the floor at an angular speed of 4 rotations per second. What is its speed in degrees persecond? Hint: One full rotation equals 360 degrees.

Answers

Speed in degrees per second or angular speed will be 25.13 radian

What is an angular speed?

Angular speed is defined as the rate of change of angular displacement and can be expressed as angular rotation / time

Total number of rotations = 4

one rotation makes an angle of = 360° = 2 π radian

coil is rolling at an angular speed of 4 rotation / second

4 rotations will make = 2π * 4 = 25.13 radian

hence , speed in degrees per second or angular speed will be 25.13 radian

Learn more about angular speed :

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If there are 4 rotations per second and 360 degrees in 1 rotation, the angular speed is 1440 degrees per second. (4 * 360)

Usually angular speed is measured in radians though.

Deimos completes one (circular) orbit of Mars in 1.26 days. The distance from Mars to Deimos is 2.35×107m. What is the centripetal acceleration of Deimos?

Answers

Answer:

The centripetal acceleration of Deimos is $0.077m/s^(2)$ .

Explanation:

The centripetal acceleration is defined as:

$a = (v^(2))/(r)$ (1)

Where v is the velocity of Deimos and r is the orbital distance.

Notice that is necessary to determine the velocity first.

The speed of the Deimos can be found by means of the Universal law of gravity:

$F = G(M \cdot m)/(r^(2))$ (2)

Then, replacing Newton's second law in equation 2 it is gotten:

$m\cdot a = G(M \cdot m)/(r^(2))$ (3)

However, a is the centripetal acceleration since Deimos almost describes a circular motion around Mars:

$a = (v^(2))/(r)$ (4)

Replacing equation 4 in equation 3 it is gotten:

$m(v^(2))/(r) = G(M \cdot m)/(r^(2))$

$m \cdot v^(2) = G (M \cdot m)/(r^(2))r$

$m \cdot v^(2) = G (M \cdot m)/(r)$

$v^(2) = G (M \cdot m)/(rm)$

$v^(2) = G (M)/(r)$

$v = \sqrt{(G M)/(r)}$ (5)

Where v is the orbital speed, G is the gravitational constant, M is the mass of Mars, and r is the orbital radius.

$v = \sqrt{((6.67x10^(-11)N.m^(2)/kg^(2))(6.39x10^(23)kg))/(2.35x10^(7)m)}$

$v = 1346m/s$

Finally, equation 4 can be used:

$a = ((1346m/s)^(2))/(2.35x10^(7)m)$

$a = 0.077m/s^(2)$

Hence, the centripetal acceleration of Deimos is $0.077m/s^(2)$ .

Final answer:

The centripetal acceleration of Deimos, one of Mars' moon, can be calculated using its orbital period and distance from Mars. Convert the time units to seconds and use the formulas for velocity and centripetal acceleration to get an answer of approximately 7.84x10^-5 m/s^2.

Explanation:

To find the centripetal acceleration of Deimos, we can use the formula for centripetal acceleration, which is a =v^2/r , where v is the velocity and r is the radius (distance from Mars to Deimos). The velocity can be found using the formula v = 2πr/T, where T is the period (time for one complete orbit).

First, convert the days into seconds because the SI unit of time in physics is second. So, 1.26 days = 1.26 * 24 * 60 * 60 = 108864 seconds.

Then, calculate the velocity: v = 2 * π * 2.35x10^7m / 108864s = 1.36 km/s.

Finally, substitute v and r into the centripetal acceleration formula: a = (1.36x10^3m/s)^2 / 2.35x10^7m = 7.84x10^-5 m/s^2.

The centripetal acceleration of Deimos is approximately 7.84x10^-5 m/s^2.

Learn more about Centripetal Acceleration here:

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