A 5.0-kg object is pulled along a horizontal surface at a constant speed by a 15-n force acting 20° above the horizontal. How much work is done by this force as the object moves 6.0 m?

Answers

Answer 1
Answer:

A 5.0 kg object is pulled by a 15-N force acting 20 °C above the horizontal. After moving for 6.0 m, the work done is 85 J.

What is work?

In physics, work is the energy transferred to or from an object via the application of force along a displacement.

A 5.0 kg object is pulled by a 15-N force acting 20 ° above the horizontal. We can calculate the work done after the object moved 6.0 m using the following expression.

W = F × s × cosθ

W = 15 N × 6.0 m × cos 20° = 85 J

where,

  • W is the work.
  • F is the force.
  • s is the displacement.
  • θ is the angle between F and s.

A 5.0 kg object is pulled by a 15-N force acting 20 °C above the horizontal. After moving for 6.0 m, the work done is 85 J.

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Answer 2
Answer:

Answer:

84.6 J

Explanation:

The work done by the force is given by

W=Fd cos \theta

where

W is the work done

F = 15 N is the force applied

d = 6.0 m is the displacement

\theta=20^(\circ) is the angle between the force's direction and the displacement

Substituting the numbers into the equation, we find

W=(15 N)(6.0 m)cos 20^(\circ) =84.6 J


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Why are both accuracy and reproducibility important in making a measurement?

Answers

accuracy is how close you're measurement comes to an accepted or given value. I n many cases you do not know what the accepted value is, so you have nothing to compare your measurement with. The more often a measurement is taken with close precision, or reproducibility, the more likely you are to being close to your unknown accepted value.
There is a great short tutorial video covering accuracy and precision at Sciocity dot com

Joan makes the device shown in her science class.An illustration with a battery and ends labeled positive and negative. A wire is connected to the positive end of the battery and curls around an iron nail and connects back with the negative side of the battery.

What would happen to the magnetic field if she connects the battery in the opposite direction?

The field would stop.
The field would get stronger.
The field would reverse its poles.
The field would get weaker.

Answers

If she connects the battery in the opposite direction, the magnetic field would reverse its poles.

What is magnetic field?

The magnetic field is the region of space where an object experiences the magnetic force and obtain magnetic properties.

A wire is connected to the positive end of the battery and curls around an iron nail and connects back with the negative side of the battery. This arrangement will let the current flow from the positive end of the battery towards the negative terminal of the battery.

If the battery is connected in the opposite direction, the current will flow from negative to positive terminal.

Therefore, If she connects the battery in the opposite direction, the magnetic field would reverse its poles.

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Answer:

The field would reverse its poles.

Explanation:

The current flow will reverse directions which will reverse the poles in the magnetic field created around the iron nail.

A 2.0 m tall object is 12.0 m from a convex lens that has a 4.0m focal length. Determine the image size and distance from the
lens.?

Answers

Great question! To determine the image size and distance from the lens, we can use the lens formula:

1/f = 1/v - 1/u

where f is the focal length of the lens, v is the image distance, and u is the object distance.

Given that the focal length (f) is 4.0 m and the object distance (u) is 12.0 m, we can substitute these values into the formula:

1/4 = 1/v - 1/12

To solve for v, we need to rearrange the equation:

1/v = 1/4 + 1/12

1/v = (3 + 1)/12

1/v = 4/12

1/v = 1/3

Now, we can find the value of v by taking the reciprocal of both sides:

v = 3 meters

So, the image distance (v) is 3 meters.

To find the image size, we can use the magnification formula:

magnification (m) = -v/u

Given that the object height (h) is 2.0 meters, we can substitute these values into the formula:

m = -v/u = -3/12 = -1/4

The negative sign indicates that the image is inverted. The magnification value of -1/4 means that the image is one-fourth the size of the object.

Therefore, the image size is 1/4 of the object's height, which is 1/4 * 2.0 = 0.5 meters.

So, the image size is 0.5 meters and the image distance is 3 meters from the convex lens.

I hope this explanation helps! Let me know if you have any further questions.

Which method of calculating volume would you use if the object is irregulary shaped?

Answers

Use a graduated cylinder filled halfway with water. Place the object inside, and measure the difference of the water level before and after you put said object in the water. 

...Also this is elementary/middle school science

A ball rolls down an incline with an acceleration of 10 cm/s^2. If it starts with an initial velocity of 0 cm/s and has a velocy of 50 cm/s when it reaches the bottom of the ramp, how long is the ramp?

Answers

Given a = 10 cm/s²
          u = 0 cm/s
          v = 50 cm/s
we know that 
         v²=u²+2aS
        2500=2×10×S
        2500÷20 = S
        S= 125 cm
The ramp is 125 cm

Final answer:

The time for the ball to reach the bottom of the ramp is 5 seconds. Using this time value, the acceleration, and the initial velocity, you can calculate the length of the ramp, which is found to be 125 cm.

Explanation:

The question involves the physics principles of kinematics, specifically the concept of acceleration. Given that the initial velocity is 0 cm/s, the final velocity is 50 cm/s, and the acceleration is 10 cm/s^2, you can find the time it took for the ball to reach the bottom using the formula vf=vi+at (Final velocity = initial velocity + acceleration * time). Substituting the given values, you get the equation 50cm/s = 0cm/s + 10cm/s^2 * time, simplifying which gives time = 5 seconds.

To find the length of the ramp, you can use another kinematic equation, d = vit + 0.5at^2 (Distance = initial velocity * time + 0.5 * acceleration * time^2). Substituting the values we know, (initial velocity = 0, acceleration = 10 cm/s^2, time = 5 s), the equation simplifies to d = 0*5 + 0.5*10*5^2 = 0 + 0.5*10*25 = 125 cm. Therefore, the length of the incline or ramp is 125 cm.

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Neon has 10 protons and 10 electrons. How many additional electrons would it take to fill the outer (second) electron shell?

Answers

none because Neon is already stable