There are 3 times as many pears are oranges. If a group of children receive 5 oranges each,there will be no left over.If the same group of children receive 8 oranges each, there will be 21 pears left over. How many oranges are there?

Answers

Answer 1
Answer:

There are 15 oranges

Solution:

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

There are 3 times as many pears are oranges

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

If a group of children receive 5 oranges each, there will be no left over

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

If the same group of children receive 8 oranges each, there will be 21 pears left over

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

Substitute eqn 1

3x = 8c + 21 ---- eqn 3

Substitute eqn 2

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

Substitute c = 3 in eqn 2

x = 5(3)

x = 15

Thus there are 15 oranges

Answer 2
Answer:

Answer:

15 orangs

Step-by-step explanation:

There are 15 oranges

Solution:

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

There are 3 times as many pears are oranges

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

If a group of children receive 5 oranges each, there will be no left over

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

If the same group of children receive 8 oranges each, there will be 21 pears left over

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

Substitute eqn 1

3x = 8c + 21 ---- eqn 3

Substitute eqn 2

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

Substitute c = 3 in eqn 2

x = 5(3)

x = 15

Thus there are 15 oranges


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What value of x is in the solution set of 2(3x – 1) ≥ 4x – 6?–10
–5
–3
–1

Answers

If you would like to solve the inequation 2 * (3x - 1) >= 4x - 6, you can do this using the following steps:

2 * (3x - 1) >= 4x - 6
2 * 3x - 2 * 1 >= 4x - 6
6x - 2 >= 4x - 6
2x >= - 6 + 2
2x >= - 4
x >= - 2

The correct result would be x >= - 2, so - 1.

The value of x in the solution is -1. Option D

How to determine the value of x

2(3x – 1) ≥ 4x – 6

From the given equation, make 'x' the subject by expanding the brackets

6x - 2 ≥ 4x - 6

Collect like terms

6x -4x ≥ -6 + 2

2x ≥ -4

x ≥ -4/ 2

x ≥ -2

If x ≥ -2, then x = -1

Therefore, the value of x in the solution is -1.Option D

Learn more about inequalities here:

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What's the answer ? ..... ​

Answers

Answer:

B) 10m^3(m^3+2)

Step-by-step explanation:

Hope this helps

Answer: B.
Explanation: when you distribute 10m^3 and multiply it to just m^3, you add the exponents which would give you 10m^6 then 10m^3 multiplied by just 2 will give you 20m^3. Which all together will be the initial problem 10m^6+20m^3

What is 6 3/4 of 7,600.00

Answers

Answer:

Step-by-step explanation:

6 3/4 = 27/4

7600 * 27/4 =  205200/4

51300

The scatter plot shows the ages of children and how many stuffed animals they own.What is the range of ages for the cluster?

Answers

the answer is 8 to 10 that is the range of ages for the cluster

The function y=-16x^2+96x shows the height y of a football kicked off the ground over a period of time x.the graph of the function is shown below.what is a reasonable domain for the time the ball is in the air

Answers

the domain is 0 < x < or equal to 6 seconds

Answer:

Domain:

(−∞,∞),{x|x∈R}

Step-by-step explanation:

hope i helped :) !!

Find the area of a regular octagon with apothem K and side of 10.40K
60K
80K

????

Answers

Answer: 40K

Step-by-step explanation:

We know that the area of a regular polygon is given by :-

A=(1)/(2)*Apothem*Perimeter

Given: The side of regular octagon = 10

Then, the perimeter of the regular octagon =8(side)=8(10)=80

Now, the area of given regular octagon is given by :-

A=(1)/(2)*K*80\n\Rightarrow\ A=40K