CHEMISTRY COLLEGE

The length of the marathon race is approximately 26.2 mi. What is the distance in kilometers?

Answers

Answer 1

Answer:

Answer : The distance in kilometers is, 42.2 km

Explanation :

As we are given that the length of the marathon race is 26.2 mile. Now we have to determine the distance in kilometers.

The conversion used for distance from mile to kilometer is:

1 mile = 1.609 km

As, 1 mile = 1.609 km

So, 26.2 mile = $\frac{26.2\text{ mile}}{1\text{ mile}}* 1.609km$

= 42.2 km

Thus, the distance in kilometers is, 42.2 km

Answer 2

Answer:

Answer: 42.16481

Explanation:

Related Questions

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100.0 mL of Ca(OH)2 solution is titrated with 5.00 x 10–2 M HBr. It requires 36.5 mL of the acid solution for neutralization. What is the number of moles of HBr used, and the concentration of the Ca(OH)2 solution, respectively?
Weathering and erosion can turn metamorphic rock into sediment. Which of the following processes would turn that sediment into sedimentary rock? * 10 points weathering and erosion compaction and cementation heat and pressure melting

Which of the following chemicals is potentially dangerous?A. ammonium nitrate

B. ethyl alcohol

C.sulfuric acid

D.All chemicals are potentially dangerous

Answers

Answer:

D.All chemicals are potentially dangerous

Explanation:

No chemical is toxicologically neutral

The balanced equation below shows the products that are formed when pentane (C5H12) is combusted.C5H12 + 802 → 10CO2 + 6H20
What is the mole ratio of oxygen to pentane?

Answers

Answer:

8 : 1

Explanation:

The balanced equation for the reaction is given below:

C5H12 + 8O2 → 5CO2 + 6H2O

From the balanced equation above,

1 mole of C5H12 reacted with 8 moles of O2.

Thus the mole ratio of O2 to C5H12 is:

8 : 1

Answer:

8:1 !!!

Explanation:

I Just take the test

Use molecular orbital theory to determine whether f22+ is paramagnetic or diamagnetic.

Answers

We have to know whether F₂²⁺ is paramagnetic or diamagnetic.

F₂²⁺ is paramagnetic.

If number of unpaired electron in any species is equal to zero, the species is diamagnetic and the species contains unpaired electrons, then the species is paramagnetic.

The magnetic property can be explained using molecular orbital theory.

Total number of electron present in F₂²⁺ is equal to 16 (i.e, 9+9-2). From the molecular orbital electronic configuration, number of electrons present in pi orbitals present is equal to 2.

So, F₂²⁺ is paramagnetic.

Answer : $F_2^(2+)$ is paramagnetic.

Explanation :

According to the molecular orbital theory, the general molecular orbital configuration will be,

$(\sigma_(1s)),(\sigma_(1s)^*),(\sigma_(2s)),(\sigma_(2s)^*),[(\pi_(2p_x))=(\pi_(2p_y))],(\sigma_(2p_z)),[(\pi_(2p_x)^*)=(\pi_(2p_y)^*)],(\sigma_(2p_z)^*)$

As there are 9 electrons present in fluorine.

The number of electrons present in $F_2^(2+)$ molecule = 2(9) - 2 = 16

The molecular orbital configuration of $F_2^(2+)$ molecule will be,

$(\sigma_(1s))^2,(\sigma_(1s)^*)^2,(\sigma_(2s))^2,(\sigma_(2s)^*)^2,(\sigma_(2p_z))^2,[(\pi_(2p_x))^2=(\pi_(2p_y))^2],[(\pi_(2p_x)^*)^1=(\pi_(2p_y)^*)^1],(\sigma_(2p_z)^*)^0$

Paramagnetic compounds : They have unpaired electrons.

Diamagnetic compounds : They have no unpaired electrons that means all are paired.

The number of unpaired electron in molecule is, 2. So, this is paramagnetic. That means, more the number of unpaired electrons, more paramagnetic.

Thus, is paramagnetic.

Using the balanced equation below,how many grams of carbon dioxide
would be produced from the
complete reaction of 83.7 g carbon
monoxide?
Fe2O3 + 3CO → 2Fe + 3CO2

Answers

131.6 grams of carbon dioxide would be produced from the complete reaction of 83.7 g carbon monoxide.

The balanced chemical equation is given below.

Fe2O3 + 3CO → 2Fe + 3CO2

Calculation,

Since, 28g of carbon dioxide produces 44g of carbon monoxide.

So, 83.7 g of carbon dioxide produces 44×83.7/28 grams

83.7 g of carbon dioxide produces 131.6 grams

What is chemical equation?

The symbolic representation of chemical reaction in which reactant represents in left side and product represents in right side is called chemical equation.

To learn more about chemical equation here.

brainly.com/question/21049751

#SPJ3

Answer:131.6 g

Explanation:

Chemistry work here. Please help as soon as possible. I have allot of questions that needs to be answered. Can someone do it for me?

Answers

Answer:

I dont know about the yield but I think mno2 is the limiting reactant

When 282 gr of glycine are dissolved in 950 gr of a certain mystery liquid, the freezing point of the solution is 8.2 C less than the freezing point of pure. Calculate the mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point. The van't Hoff factor for iron(III) chloride in X. Be sure your answer has a unit symbol, if necessary, and round your answer to significant digits.

Answers

Answer: $1.4* 10^2g$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i* K_f* m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte like glycine)

$K_f$ = freezing point constant = ?

m= molality

$\Delta T_f=i* K_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}$

Weight of solvent = 950 g = 0.95 kg

Molar mass of glycine = 75.07 g/mol

Mass of glycine added = 282 g

$8.2=1* K_f* (282g)/(75.07 g/mol* 0.95kg)$

$K_f=2.2^0C/m$

Thus freezing point constant is $2.2^0C/m$

2) $\Delta T_f=i* K_f* m$

$\Delta T_f=T_f^0-T_f=8.2^0C$ = Depression in freezing point

i= vant hoff factor = 4 (for $FeCl_3$ )

$K_f$ = freezing point constant = $2.2C/m$

m= molality

$\Delta T_f=i* K_f* \frac{\text{mass of solute}}{\text{molar mass of solute}* \text{weight of solvent in kg}}$

Weight of solvent = 950 g = 0.95 kg

Molar mass of $FeCl_3$ = 162.2 g/mol

Mass of $FeCl_3$ added = ?

$8.2=4* 2.2* (xg)/(162.2 g/mol* 0.95kg)$

$x=1.4* 10^2g$

Thus mass of iron(III) chloride that must be dissolved in the same mass of to produce the same depression in freezing point is $1.4* 10^2g$

Answer:

$mass_(FeCl_3)=1.5x10^2gFeCl_3$

Explanation:

Hello,

In this case, by using the given data for glycine, one computes the freezing point constant of the mystery liquid as shown below, considering the molality of the glycine and its van't Hoff factor equal to the unity:

$\Delta T=i*Kf*m_(Glyc)\n\nKf=(\Delta T)/(i*m_(glyc)) =(8.2^oC)/(1*(282gGlyc)/(950gX)*(1molGlyc)/(75.07gGlyc)*(1000gX)/(1kgX) ) \n\nKf=2.1^oC/m$

Now, as we are looking for the mass of iron(III) chloride at the same conditions of the aforesaid case, at first, one solves for the molarity of such compound considering that its theoretical van't Hoff factor is 4 as follows:

$m_(FeCl_3)=(\Delta T)/(i*Kf) =(8.2^oC)/(4*2.1^oC/m_(FeCl_3)) =0.98m$

Now, one obtains the requested mass via:

$mass_(FeCl_3)=0.98(molFeCl_3)/(kgX)*0.95kgX*(162.35gFeCl_3)/(1molFeCl_3) \n\nmass_(FeCl_3)=151.1gFeCl_3\nmass_(FeCl_3)=1.5x10^2gFeCl_3$

Best regards.

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