40 = 90^2/16 sinx cosx find x

Answers

Answer 1

Answer:

Answer:

x = 4.545

Step-by-step explanation:

Given the expression

$40=(90^2)/(16) sinxcosx\n\nCross\ multiplying;\n\n16*40 = 90^2 sinxcosx\n\n640 = 90^2 sinxcosx\n\n(640)/(8100) = sinxcosx\n from\ trig\ identity, sin2x = 2sinxcosx\nsinxcosx = sin2x/2\n$

$Hence, \ (640)/(8100) = (sin2x)/(2) \n\n(2*640)/(8100) = sin2x\n \n(1280)/(8100)=sin2x\n \n0.158 = sin2x\n\n2x = sin^(-1) 0.158\n\n2x = 9.09\nx = 9.09/2\nx =4.545$

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The side length of a square ice cube is claimed to be 1.0 inches, correct to within 0.001 inch. Use linear approximation to estimate the resulting error, measured in squared inches, in the surface area of the ice cube.

Answers

Answer:

0.012

Step-by-step explanation:

Linear approximation says that,

$f(x) \approx f(x_o)+f'(x_o)(x-x_o)$

For a cube the surface area is $6x^2$ .

So the side is 1.0 inch in, the surface area is $=6*1^2 = 6$ square inches.

In Linear approximation means you ignore the term $x_o^2$ , if $x_o$ is a small number, because then $x_o^2$ will be a very smalle number and that does not contribute much to the error.

So the surface area is approximately,

$6x^2=6x_o^2+12x_o(x-x_o)$

So here, $x=1.001, x_o=0.001$

The error in the area is approximately,

$12 * 0.001=0.012$

So the error is 0.012.

Shureka Washburn has score of 72,67,82, and 79 on her alebra test. Use an inequality to find the scores she must make on the final exam to pass the course with an average of 77 or higher, given that the final exam counts as two test.

Answers

Answer:

$x \geq 81$

Step-by-step explanation:

Shureka Washburn has score of 72,67,82, and 79 on her algebra test.

Let x be the score on the final exam.

$(72+67+82+79+x+x)/(6) \geq 77$

=> $(300+2x)/(6) \geq 77$

=> $300+2x \geq(77)6$

=> $300+2x \geq 462$

=> $2x \geq 462-300$

=> $2x \geq 162$

=> $x \geq 81$

72+67+82+79=300
300/4=75
300+81+81=462
462/6=77

ANSWER X MUST BE GREATER THAN OR EQUAL TO 81

Pleas helpThe cube has a volume of 27 in3.

Find the volume of a scaled image with a scale factor of 2.

? in3

Cube with a side length of three inches

Answers

Actual cube has sides ∛27 = 3 inches.

When you scaled it with a factorof two, each side will become 3 x 2 = 6 inches.

The volume of the new cube is (6 in)^3 = 216 in^3

Realize that you could calculate it by raising the scale factor to the third power.

2^3 = 8

27 x 8 = 216

*- 27 cubed by 2!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

1)simplify the expression (2x)^4

2)the perimeter of a rectangular is twice the sum of its length and its width. the perimeter is 16 meters and its length is 2 meters more then twice its width

3)Find the real numbers x and y that make the equation true.

-3 + yi = x + 6i

Answers

$(2x)^4=16x^4$
------------------------------------------
$2(l+w)=16\n l=2w+2\n\n 2(2w+2+w)=16\n 6w+4=16\n 6w=12\n w=2\n\n l=2\cdot2+2\n l=6$
-------------------------------------------
$-3+yi=x+6i\Rightarrow x=-3 \wedge y=6$

You toss 3 fair coins in the air at once.a) List the sample space.
b) What is the probability of getting all 3 heads?
c) What is the probability of getting all 3 tails?
d) What is the probability of getting 1 head and 2 tails?
e) What is the probability of getting 1 tail and 2 heads?
f) What do the probabilities from parts b through e add up to?

Answers

The probability of a head or tail upon flipping is 50-50. THe asnwers are as followsL
a. {HHH, HHT, HTT, TTT, TTH, THH, HTH, THT}b and c. p = 3C3 * 0.5^3 = 0.125d. from a, p = 3/8 = 0.375e. from a, p = 3/8 = 0.375f. 0.875

Anyone know?
A. 99
B. 100
C. 121
D. Cannot be determined