For given isosceles triangle ΔMKL with MK≅ML, x=9; MK=48, KL=31, ML=48.
An isosceles triangle has two of its 3 sides congruent.
For given ΔMKL, MK is congruent to ML (MK ≅ ML); i.e. length of side MK is equal to length of the side ML.
Given:
MK=7x-15
KL=4x-5
ML=10x-42
Equating MK with ML, we get:
MK=ML
7x-15 = 10x-42
Taking all x terms to the right,
42-15 = 10x-7x
27 = 3x
x=9
To find measure of each side MK, ML and KL; substitute the value of x=9 in corresponding equations.
MK = 7x-15
= (7×9) - 15
= 63-15
= 48
KL = 4x-5
= (4×9)-5
= 36-5
= 31
ML = 10x-42
= (10×9)-42
= 90-42
= 48
Therefore, for given ΔMKL with MK≅ML, x=9; MK=48, KL=31, ML=48.
0.8
5
0.569
The theoretical probability of winning a medium prize at the duck pond is 0.2, Hence option A is correct.
What is probability?
Probability is the ratio of number of favorable outcomes and total number of outcomes. it deals with finding out the likelihood of the occurrence of an event.
According to the given information,
Number of medium-prize winning ducks = 13
The total number of ducks = 65
The theoretical probability of winning a medium prize at the duck pond can be found by dividing the number of medium-prize winning ducks (13) by the total number of ducks (65).
So, the probability of winning a medium prize is,
= 13/65
= 0.2 or 20%
Therefore, the theoretical probability of winning a medium prize at the duck pond is 0.2 or 20%.
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Hi there! :) I believe the answer is 0.2. The way I got 0.2 is because there are 13 medium-sized ducks and there are 65 total ducks floating I did 13/65( 13 divided by 65) which equals 0.2. For theoretical probability you divide by the number of outcomes.
Hoped I helped! :D
Answer:
make better picture
Step-by-step explanation:
This question is based on the concept of graphical method. Therefore, In 4 years, human years will both pets be the same age in their respective types of years.
Given:
Your dog is 16 years old in dog years.
Your cat is 28 years old in cat years.
For every human year, your dog ages by 7 dog years and your cat ages by 4 cat years.
Let x be the no. of human yrs.
We have to find x such that age is same for dog and cat in their respective year i.e.
16 + 7x = 28 + 4x
Write above equation as follows and solve it graphically,
y = 16 + 7x
y = 28 + 4x
From the graph, it is observe that. Attachment is below.
Point of intersection is (4, 44). Thus, solution of equation is x =4.
Now put the value x = 4 in equation 16 + 7x = 28 + 4x.
We get,
16 + 7(4) = 28 + 4(4)
44 = 44
Therefore, In 4 years, human years will both pets be the same age in their respective types of years.
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Hey there! Let me help you out!
No, this is not true. The answer to your question is: 351800<605908. This means that 605908 is bigger than 351800. To find this out, count how many digits there are in both the numbers. The number with more digits is bigger than the other number. If both the numbers have the same number of digits, then see the starting number of each number and so forth, if they are the same. For example, for this question, count how many numbers there are in each number. They both have 6 numbers so u can't make out anything from that. Next see the starting number for each of them. In 351800, the starting number is 3. In 605908, the starting number is 6. Since 6 is larger than three, 605908 is bigger than 351,800.
Thank you! Hope it helps!