A store is having a sale on where movies are 15% of their original price. A movie is on sale for $22.10. What is the original price of the movie?

Answers

Answer 1

Answer:

Answer:

$147.33

Step-by-step explanation:

In order to solve this problem we just have to do a quick reasoning, the problem states that the movies are being sold for the 15% of their original price, so 22.10 represents the 15% of the original price, with this we can just do a rule of thirds to be able to calculate how much is the 100%.

$(15)/(100)= (22.1)/(x)$

Now if we just clear the x we can solve the equation for X.

$x=((22.10)(100))/(15)$

$x=(2210)/(15) \nx=147.33$

So the original price would be 147.33

Answer 2

Answer: ok so first off understand what they are saying. there is a movie on sale for $22.10 which is 15 percent of the original price. So now what you do is set up the problem.

22.10 is = 15% of the price

x = 100% of the price (original price)

15 = 22.10
100 x

now just use cross multiplication.

15x = 22.10 · 100

solve for x.

15x = 2210
15 15

x = 147.33333333 since the 3's go on forever you can simply put it into a fraction

x = 147 3
9

whenever there is a repeating number you can put it into a fraction but putting the repeating number over a 9

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Use scientific notation to find the product of 20.5 × 10^7 and 0.000036."

Answers

You can express 0.000036 as 3.6 × 10^-5 (we move the decimal 5 places left)

Then we find 3.6 × 10^-5 × 20.5 × 10^7
The exponents add to become just 10^2.
3.6 × 20.5 = 73.8

73.8 × 10^2 is our answer...
In proper scientific notation, this is 7.38 × 10^3. (the left # should be <10)
In standard notation, this is 7380. (we move the decimal 3 places right)

With RedRicin's Explantion, the formula gets simplified to 7.38 x 10^3

Someone rolls a six sided fair die 5 times. They consider it a success if they have a two or three on a die. Whats the probability of 2 successes? no successes? and at least 3 successes?

Answers

Answer:

2 successes = 80/243

0 successes = 32/243

at least 3 successes = 51/243

Step-by-step explanation:

Lets suppose we had the following sequence of 5 throws:-

2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws

Probability of this is

1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243

There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).

So Prob(2 successes) = (8/243) * 10 = 80/243

Prob ( No successes) = (2/3)^5 = 32/243

Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3

4/243 * 10 = 40 / 243

Probability of 4 successes = (1/3)^4 * 2/3 * 5C4

= 10/243

Probability of 5 success = (1/3)^5 = 1 / 243

Prob(at least 3 successes) = 51/243

Answer:

2 successes = 80/243

0 successes = 32/243

at least 3 successes = 51/243

Step-by-step explanation:

Lets suppose we had the following sequence of 5 throws:-

2 or 3, 2 or 3 , then NOT 2 or 3 on last 3 throws

Probability of this is

1/3 * 1/3 * 2/3 * 2/3 * 2/3 = 8/243

There are (5*4) / 2 = 10 ways of having this result ( that is the number of combinations of 2 from 5 = 5C2 ).

So Prob(2 successes) = (8/243) * 10 = 80/243

Prob ( No successes) = (2/3)^5 = 32/243

Probability of 3 successes = 1/3 * 1/3 * 1/3 * 2/3 * 2/3 * 5C3

4/243 * 10 = 40 / 243

Probability of 4 successes = (1/3)^4 * 2/3 * 5C4

= 10/243

Probability of 5 success = (1/3)^5 = 1 / 243

Prob(at least 3 successes) = 51/243

1) •There were 3,905 more hits on the schools website in January than February. •Feb. = 9854 hits.
•How many hits to the schools website have during both months?

A) About how many hits did the website have during Jan and Feb?

B) exactly how many hits did the website have during Jan and Feb?

Answers

Let

x---------> the number of hits in January

y---------> the number of hits in February

we know that

$x=3,905+y$ --------> equation $1$

$y=9,854$ --------> equation $2$

Substitute equation $2$ in equation $1$

$x=3,905+9,854$

$x=13,759$

Part a) About how many hits did the website have during Jan and Feb?

$x=13,759$ ----> Round to nearest ten thousand-----> $x=14,000$

$y=9,854$ ----> Round to nearest ten thousand-----> $x=10,000$

$x+y=14,000+10,000=24,000$

the answer part a) is $24,000$

Part b) Exactly how many hits did the website have during Jan and Feb?

$x+y=13,759+9,854=23,613$

the answer part b) is $23,613$

In January, there were 13,759 hits and in February there were 9,854 hits.
During both the months, there were 23,613 hits to the school's website.

Some one may you please help (Find the unit rate) in 1/6 hour, adam jogs 7/10 mile

Answers

10 min per 7/10 miles
1min = .07 miles

There are 20 students in your class 3/5 of them pack a lunch which meant that will help you find the number of students in your class who pack a lunch

Answers

so 3/5 of 20 is what
'of' means multiply

3/5 of 20 means
3/5 times 20/1=(3*20)/(5*1)=60/5=12/1=12

12 pack a lunch

Solve this Equation 10x+2=32

Answers

x=3 ,is the answer.

The equation given: 10x+2 = 32

10x+2=32

10x=30

x=30/10

x=3

What is the best definition of an equation?

The equation is defined as the state of an equation, often expressed as an equation with equal values on both sides, or refers to a problem that needs to be considered a lot. An example equation is 2 + 2 = 3 + 1

. Linear equations have only one or two variables. Variables in linear equations are powers of 1 and are not used as the denominator of fractions. If you find a pair of values that make the linear equation true and plot those pairs on the coordinate grid, all the points are on the same line.

Learn more about equations here:brainly.com/question/13763238

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10x+2=32
10x=30
1=3
3=x

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