How many Btu per hour are lost through a 100-square foot wall that is made up of a 12-inch thick concrete block wall with an R value of 1.89 and 4 inches of fiberglass insulation with an R value of 14.8? The inside temperature is 65 degrees F and the outside temperature is 15 degrees F.

Answers

Answer 1
Answer:

Answer:

300 Btu per hour

Explanation:

given data

area = 100-square foot

thick = 12 inch

R value at 12 = 1.89

R value at 4 = 14.8

inside temperature = 65 degrees F

outside temperature = 15 degrees F

to find out

How many Btu per hour

solution

we get here How many Btu per hour that is express as

Btu per hour = (area*temp\ difference)/(r\ value\ 12 + r\ value\ 4)   ............1

put here value we get

Btu per hour = (100(65-15))/(1.89+14.8)

Btu per hour = 299.580

so Btu per hour is 300 Btu per hour


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Answers

Answer: The correct answer is "a moving charged particle".

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If the current flowing in the conductor then there is magnetic field around the wire which can be detected by the compass needle.

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If you squeeze the bottom of a closed tube of toothpaste, the pressure is increased ____.

Answers

The cap will pop of,THE SEAL WILL BREAK, or the tube will explode.
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Will amplitude change if the pitch gets louder

Answers


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A person walks 25 m west and then 45 m at the angle of 60 degrees north of east what is the magnitude of the total displacement?

Answers


To solve this question, we need to use the component method and split our displacements into their x and y vectors. We will assign north and east as the positive directions.

The first movement of 25m west is already split. x = -25m, y = 0m.

The second movement of 45m [E60N] needs to be split using trig.
x = 45cos60 = 22.5m
y = 45sin60 = 39.0m

Then, we add the two x and two y displacements to get the total displacement in each direction.

x = -25m + 22.5m = -2.5m
y = 0m + 39.0m

We can use Pythagorean theorem to find the total displacement.
d² = x² + y²
d = √(-2.5² + 39²)
d = 39.08m

And then we can use tan to find the angle.
inversetan(y/x) = angle
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If an alloyed guitar B string (147 Hz resonance) has an average diameter of .6 mm over an effective oscillating length of 65 cm, what is the tension in Newtons if the alloy is 10% aluminum and 90% copper? (assume the specific gravities of the metals are 2.6 and 8.9 grams per cubic centimeter, respectively)

Answers

Answer:

73.8 N

Explanation:

The total volume is,

V = (m_Al)/(P_Al) = (m_copper)/(P_copper)

=  (10m)/((100)(2.6)) = (90m)/((100)(8.9))

= 0.1396 m

The average  density is,

p = (m)/(V)

= (m)/(0.1396)

= 7.169 g/cm³

The linear mass density is,

μ = pπr²

= (7.169 x 10⁹) (π (0.3 x 10⁻³)²)

= 2.026 x 10⁻³ Kg/m

The fundamental mode of length is,

L =  λ/2

λ=2L

= 2 x 0.65

= 1.3 m

The speed of the wave is,

v = λf

= 1.3 m x 147 Hz

= 1.91 m/s

The tension is,

v =  √T/ц

T = ц v²

= 2.026 x 10⁻³)(1.91 m/s)²

= 73.769N

73.8N