The frequency polygon shows the distances thrown by the entrants in the University and College Discus Finals at the 2003 Drake Relays. What percent of the entrants had distances between 150 and 160 feet? Round your answer to two decimal places

Answers

Answer 1
Answer:

Answer:

70.83% entrants will have distances between 150 and 160.

Step-by-step explanation:

This question is incomplete without an attachment; here is the attachment enclosed with the answer.

From the graph attached,

Number of entrants having distances between 150 and 160 feet = 8 + 9 = 17

Number of entrants between 140 and 200 feet = 8 + 9 + 4 + 2 + 1 = 24

Percent of entrants having distance between 150 and 160 feet = \frac{\text{Number of entrants between 150 and 160}}{\text{Number of total entrants}}* 100

= (17)/(24)* 100

= 70.83%

Therefore, 70.83% entrants will have distances between 150 and 160.

Answer 2
Answer:

Final answer:

To find the percent of entrants with distances between 150 and 160 feet in the frequency polygon, calculate the area of the rectangle between the two values and divide it by the total area under the polygon. Multiply the result by 100 to get the percent.

Explanation:

To find the percent of entrants with distances between 150 and 160 feet, we need to look at the area under the frequency polygon between the two values. Since the frequency polygon represents the distribution of distances, we can estimate the percent by calculating the proportion of the area under the polygon between 150 and 160 feet. First, find the total area under the polygon by adding up the areas of all the rectangles formed by the frequency values and the width of each interval. Then, calculate the area of the rectangle between 150 and 160 feet by multiplying the frequency of that interval by its width. Finally, divide the area of the rectangle by the total area under the polygon and multiply by 100 to get the percent.

Example:

  1. Total area under the polygon = Sum of (Frequency x Width) = (5 x 10) + (10 x 10) + (30 x 10) + (40 x 10) + (15 x 10) = 500
  2. Area of rectangle between 150 and 160 feet = Frequency x Width = 40 x 10 = 400
  3. Percent of entrants with distances between 150 and 160 feet = (Area of rectangle / Total area) x 100 = (400 / 500) x 100 = 80%

Learn more about frequency polygon here:

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Answers

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Answers

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Answers

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Answers

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