Which of the following is the solution to the given system of equations?Begin equation . . . 3 times x plus y equals . . . 6 . . . end equation
Begin equation . . . 2 times x plus 2 times y equals . . . 4 . . . end equation

A
begin ordered pair, 2, zero, end ordered pair

B
begin ordered pair, zero, 2, end ordered pair

C
begin ordered pair, negative 2, 6, end ordered pair

D
begin ordered pair, 4, negative 2, end ordered pair

Answers

Answer 1

Answer: It would be A because I think x = 2 and y = 0

Answer 2

Answer: The guy on the up is right i check and it is
A
begin ordered pair, 2, zero, end ordered pair

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Which test point holds true for 2/5x - 1/5>=0 ?

6×2p to the second power when p=5

Answers

Answer:

3600

Step-by-step explanation:

Since the question gives you p, you replace p (which is just a placeholder) with 5.

Your equation should look like this:

$(6*2(5))^2 = 3600$

joe drank 4 liters of water on monday and 4 deciliters of water on tuesday. how much more water did he drink on monday tha on tuesn

Answers

What is the unit which is required for the answer?
1 liter = 10 dl
4 l = x
x = 4*10 = 40 dl on Monday

On Tuesday - 4 dl

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Find the x-intercept and y-intercept of the line. 3x-6y=12

Answers

Answer:

the y- intercept is "3" and the x- intercept is "6"

Step-by-step explanation:

True or false. If a line L1has equation y = mx + b, where m and b are constants with m ≠ 0, then an equation of a line L2 perpendicular to L1 has the form y = -1/m x C, where C is a constant.

Answers

$L_1:y=mx+b\n\nL_2:y=-(1)/(m)\ *\ C\n\nL_1\ \perp\ L_2-FALSE\n--------------------\nL_3\ \perp\ L_1\iff L_3=-(1)/(m)+C$

Three straight lines have exactly two points of intersection. Complete the sentence below.
Two of the lines must be ....

Answers

Three straight lines have exactly two points of intersection.
Complete the sentence below.
Two of the lines must be parallel
Parallel lines never intersect
those two lines intersect third line at two points

|3k-2|=2|k+2| what is k

Answers

Answer:

k = 6

Step-by-step explanation:

|3k-2| = 2|k+2|

3k - 2 = 2k + 4

k - 2 = 4

k = 6

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