To solve the quadratic equation 4x^2 + 20x = -29 using the quadratic formula, we can first rearrange the equation to bring all terms to one side:
4x^2 + 20x + 29 = 0
Now we can identify the coefficients a = 4, b = 20, and c = 29 in the general quadratic equation ax^2 + bx + c = 0. Applying the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
Substituting the values for a, b, and c into the quadratic formula:
x = (-(20) ± √((20)^2 - 4(4)(29))) / (2(4))
Simplifying further:
x = (-20 ± √(400 - 464)) / 8
x = (-20 ± √(-64)) / 8
x = (-20 ± 8i) / 8
Now, we can simplify the expression:
x = -20/8 ± (8i)/8
x = -5/2 ± i
Therefore, the roots of the given quadratic equation are:
x = -5/2 + i
x = -5/2 - i
A.8√35
B.12√7
C.10V7
D.9V35
4 in.
actual width:
18 ft
actual length: 16 ft
The plan width is
in.
Answer:
4.5 inches
Step-by-step explanation:
Given: plan length = 4 inches, actual width = 18 feet, actual length = 16 feet
To find: plan width
Solution:
1 feet = 12 inches
Plan length = 4 inches
Actual width = 18 feet= 18× 12 = 216 inches
Actual length = 16 feet = 16× 12 = 192 inches
Plan length/plan width = actual length/actual width