Use the Distributive Property to evaluate each expression.-2(8-5)

A. -21
B. -6
C. 6
D. 18

Answers

Answer 1

Answer:

Answer: c

Step-by-step explanation:

You multiply each number by 2 and then you subtract each number then you finally get 6

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Decrease 1280 by 67%

Answers

67% of 1280 is 857.6 substrack it and it's = 422.4

Please help how do I do this?

Answers

For the first part, since you know that 4^2 in 16, which is your area, then the 2 sides are 4 square yards and 4 square yards. For the second part, you know that all sides on a square are equal so if one side is 4 square yards, then so are all the other sides. As a result, 4 times 4 is 16, your perimeter.

Final Answers: Part 1 - The length of one side is 4 yards.
Part 2 - The perimeter is 16 yards.

10x -2y = 10 in slope intercept form

Answers

slope-intercept form: y = mx + b
the point is to get y alone on one side of the equation:

10x - 2y = 10
-10x -10x
-2y = -10x + 10
-2y/-2 = -10x/-2 + 10/-2
y = 5x - 5

X + 2y ≤ 10
2x + y ≤ 8
2x - 5y < 20

Answers

Answer: answer below.

Step-by-step explanation:

To solve this system of linear inequalities, we can use a graphical method or algebraic method.

Let's start with the algebraic method.

First, let's rearrange the inequalities to solve for one variable in terms of the other.

From the first inequality, we have:

x ≤ 10 - 2y

From the second inequality, we have:

y ≤ 8 - 2x

From the third inequality, we have:

x ≤ (20 + 5y)/2

Now, let's plot the graphs of these inequalities on a coordinate plane.

Graphing the first inequality, x ≤ 10 - 2y, we start by drawing the line x = 10 - 2y. Since it is a "less than or equal to" inequality, we will draw a solid line.

Graphing the second inequality, y ≤ 8 - 2x, we start by drawing the line y = 8 - 2x. Again, since it is a "less than or equal to" inequality, we will draw a solid line.

Graphing the third inequality, x ≤ (20 + 5y)/2, we start by drawing the line x = (20 + 5y)/2. This time, since it is a "less than" inequality, we will draw a dashed line.

Now, we shade the region that satisfies all three inequalities. This region is the intersection of the shaded regions of the individual inequalities.

Finally, we can determine the solution by looking at the shaded region on the graph. The solution is the set of all points that lie within or on the boundary of the shaded region.

Alternatively, we can also solve the system of inequalities algebraically by finding the points where the lines intersect. We can then check if these points satisfy all three inequalities.

Please answer these rly simple but I'm confused still questions

Thanks!