A 67.0 kg man sits in a 5.0 kg chair so that his weight is evenly distributed on the legs of the chair. Assume that each leg makes contact with the floor over a circular area with a radius of 1.10 cm. What is the pressure exerted on the floor by each leg?

Answers

Answer 1

Answer:

Final answer:

The pressure exerted by each leg of the chair is calculated by dividing the total weight of the man and the chair (taken as a force) by the total surface area of the chair legs that is in contact with the floor.

Explanation:

To calculate the pressure exerted on the floor by each leg of the chair, we first need to calculate the total weight that the chair legs need to support. The total weight (w) is the weight of the man plus the weight of the chair, where weight is calculated as the mass multiplied by gravity (on Earth this is approx. 9.8 m/s²). So, w = (67.0 kg + 5.0 kg) * 9.8 m/s².

Next, we need to calculate the total area of all the chair legs in contact with the floor. Each leg makes contact over a circular area, the area of which (A) is calculated by 'πr²'. The total area then is 4 times this area (assuming the chair has four legs).

Pressure (P) exerted is the total force (F) applied, divided by the area (A) over which the force is distributed. Therefore the pressure exerted by each leg is the total weight divided by the total area.

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Answers

Answer: please find the attached file for the solution.

Explanation:

In a velocity time graph for the motion of the body, the total distance covered by the body is area under the graph.

Please find the attached file for the solution.

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Answers

They are too small are never in the same place. Electrons are constantly moving in random motion within the electron cloud, making them impossible to follow.

A concave mirror has a radius of curvature of 10 cm. Find the location an height of the image if the distance of the object is 8cm and the height of the object is 1.5 cm, using a scaled ray diagram

Answers

R=10
F=R/2
F=10/2=5
F=-5(CONCAVE MIRROR)
U=-8(CONCAVE MIRROR)
HEIGHT OF OBJECT=1.5
V=?
HEIGHT OF IMAGE=?
I/F=1/U+1/V
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-1/V=-1/5+1/8
-1/V=-8+5/40
-1/V=-3/40
1/V=3/40
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pyrex graduated cylinder has a volume of exactly 200 ml at 0° celsius. if it's temperature increased to 100° celsius what's volume increase or decrease compute the change in volume ?

Answers

1. The volume will increase.

2. The change in the volume is 73 mL

1. Determination of the nature of the new volume.

From the question given above, the following data were obtained:

Initial volume (V₁) = 200 mL

Initial temperature (T₁) = 0 °C = 0 + 273 = 273 K

New temperature (T₂) = 100 °C = 100 + 273 = 373 K

New volume (V₂) =?

Using the Charles' law equation, the new volume of the cylinder can be obtained as follow:

V₁ / T₁ = V₂ / T₂

200 / 273 = V₂ / 373

Cross multiply

273 × V₂ = 200 × 373

273 × V₂ = 74600

Divide both side by 273

V₂ = 74600 / 273

V₂ ≈ 273 mL

From the above calculation, we can see that the new volume increased.

2. Determination of the change in the volume.

The change in the volume can be obtained as illustrated below:

Initial volume (V₁) = 200 mL

New volume (V₂) = 273 mL

Change in volume (ΔV) =?

ΔV = V₂ – V₁

ΔV = 273 – 200

ΔV = 73 mL

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