PHYSICS HIGH SCHOOL

An object of unknown mass is initially at rest and dropped from a height h. It reaches the ground with a velocity v sin θ / g 1. The same object is then raised again to the same height h but this time is thrown downward with velocity υ1 It now reaches the ground with a new velocity υ2. How is v2 related to v1?

Answers

Answer 1

Answer:

Answer:

$v^(2)_(2)=v^(2)_(1)+(v^(2)Sin^(2)\theta )/(g^(2))$

Explanation:

Case I:

initial velocity, u = 0 m/s

Final velocity, v' = v Sinθ /g

Height = h

acceleration = g

Use third equation of motion, we get

$v'^(2)=u^(2)+2as$

$\left ( (vSin\theta )/(g) \right )^(2)=0^(2)+2gh$

$h = (v^(2)Sin^(2)\theta )/(2g^(3))$ . ... (1)

Case II:

initial velocity, u = v1

Final velocity, v = v2

height = h

acceleration due to gravity = g

Use third equation of motion, we get

$v^(2)=u^(2)+2as$

$v^(2)_(2)=v^(2)_(1)+2gh$

Substitute the value of h from equation (1) ,we get

$v^(2)_(2)=v^(2)_(1)+2g(v^(2)Sin^(2)\theta )/(2g^(3))$

$v^(2)_(2)=v^(2)_(1)+(v^(2)Sin^(2)\theta )/(g^(2))$

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The more particles a substance has at a given temperature, the more thermal energy it has. Please select the best answer from the choices provideda. True
b. False

Answers

this is true because The mass of the warm balloon is the same as the mass in the cold balloon. In the warm balloon, the gas molecules are free of each other and moving rapidly because of all the energy they have. They collide with each other and with the wall of the balloon exerting pressure, which gives the balloon its size (volume). As the balloon cools in the cooler (freezer), the air molecules transfer energy to the surrounding cooler (freezer). The molecules of air are still free of each other but they do not move as rapidly or as far apart and their collisions with the balloon walls are not as forceful. As a result the volume of the balloon containing the cool air decreases. Heat and cool only speed up or slow down the motion of the molecules. When the balloon was heated with the flame the molecules where moving so much that they transferred their heat and energy to the balloon walls causing it to pop.

Answer:

true

Explanation:

i think it is?

Predict how heat would flow if beaker A is moved so that it's touching beaker B A. Heat would flow from beaker B to beaker A.
B. No heat flow would take place between the beakers.
C. Heat would flow from both beakers.
D. Heat would flow from beaker A to beaker B.

Answers

Well,

It really depends on thier temperature. But the answer is C) Heat would flow from both beakers.

A bartender slides a beer mug at 1.7 m/s towards a customer at the end of a frictionless bar that is 1.0 m tall. The customer makes a grab for the mug and misses, and the mug sails off the end of the bar. (a) How far away from the end of the bar does the mug hit the floor? m (b) What are the speed and direction of the mug at impact?

Answers

Answer:

Explanation:

Given

velocity of mug with which it leaves the bar is 1.7 m/s

Also

height of bar=1 m

Considering motion in vertical direction

$s=u_yt+(gt^2)/(2)$

here $u_y=0$

$1=0+(9.81* t^2)/(2)$

$t=\sqrt{(2)/(9.81)}$

t=0.451 s

so horizontal distance traveled is

$R_x=ut+(at^2)/(2)$

here a=0

$R_x=1.7* 0.451=0.766 m/s$

speed of mug will be combination of horizontal and vertical velocity

$v_y=u+gt$

$v_y=0+9.81* 0.451=4.42 m/s$

$v_x=1.7 m/s$

thus $v_(net)=√(v_x^2+v_y^2)$

$v_(net)=√(4.42^2+1.7^2)$

$v_(net)=√(22.46)=4.74 m/s$

for direction

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$\theta =69$

$\theta$ is with x axis in clockwise sense

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Answers

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When evaluating promotional claims, it is important to __________.a.do your own research c.determine if there are other possible solutions b.ask if it makes sensed.all of the above

Answers

D. ALL OF THE ABOVE.

Promotional claims are given by companies to attract potential buyers with the intent of selling their goods and services.

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Please help! This is due in 10 minutes!! I will mark brainliest asap

Answers

The object is at rest. This is because time is going by and there’s no distance being added

Third option is the answer aka the object is resting hope this helps you

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