Answer:
To find the distance from the 3.0 μC point charge where the net electric field is zero in the presence of the external uniform electric field, you can use the principle that the electric fields due to the point charge and the external field will cancel each other at that point.
The electric field due to a point charge is given by Coulomb's law:
E_point_charge = k * (|q| / r^2),
where:
E_point_charge is the electric field due to the point charge.
k is Coulomb's constant (approximately 8.99 x 10^9 Nm^2/C^2).
|q| is the magnitude of the point charge (3.0 μC = 3.0 x 10^-6 C).
r is the distance from the point charge.
The external uniform electric field has a magnitude of 1.6 x 10^4 N/C. Let's denote this as E_external.
To find the point where the net electric field is zero, you want the magnitudes of the electric fields due to the point charge and the external field to be equal. So:
E_point_charge = E_external.
Substitute the expressions for both electric fields:
k * (|q| / r^2) = E_external.
Now, plug in the known values:
(8.99 x 10^9 Nm^2/C^2) * (3.0 x 10^-6 C / r^2) = 1.6 x 10^4 N/C.
Now, solve for r:
3.0 x 10^-6 C / r^2 = (1.6 x 10^4 N/C) / (8.99 x 10^9 Nm^2/C^2).
r^2 = (3.0 x 10^-6 C / (1.6 x 10^4 N/C)) * (8.99 x 10^9 Nm^2/C^2).
r^2 = (1.87 x 10^-11 m^2).
Take the square root of both sides to find r:
r ≈ 4.32 x 10^-6 m.
So, the net electric field is zero at a distance of approximately 4.32 x 10^-6 meters from the 3.0 μC point charge in the direction opposite to the external uniform electric field.
Explanation:
B. The object will move if the forces are balanced.
C. The object will move if the forces are unbalanced.
D. The object will always stay in place.
3. An object moves in the direction of the __________ force.
A. net
B. balanced
C. strongest
D. weakest
Answer:
C. The object will move if the forces are unbalanced.
A. net
Explanation:
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