PHYSICS HIGH SCHOOL

Ix identical square pyramids can fill the same volume as a cube with the same base. If the height of the cube is h units, what is true about the height of each pyramid? a.The height of each pyramid is h units.
b.The height of each pyramid is h units.
c.The height of each pyramid is h units.
d.The height of each pyramid is h units.

Answers

Answer 1

Answer:

Answer:

height of each pyramid must be 3h units

Explanation:

As we know that the volume of the cube is same as that of volume of square pyramid

so we have volume of the cube is given as

$V = h^3$

now if the base area of pyramid and the cube is same

so we will have

$V_(pyramid) = (1)/(3) Base\: Area * height$

$V_(pyramid) = (1)/(3) h^2 * y$

now since both have same volume

$(1)/(3)h^2 y = h^3$

$y = 3h$

height of each pyramid must be 3h units

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The word “cumulative” means that something builds on itself. Which example best shows how scientific knowledge is cumulative?A) Watson and Crick worked together to come up with the model of DNA.
B) Kepler based his laws of planetary motions off of Newton’s law of gravity.
C) Hardy and Weinberg independently came up with a population equation.
D) Darwin and his grandfather both worked on the ideas of survivability.

Answers

Answer: The correct answer is B.

Explanation:

"Cumulative" means that something builds on itself. Like one law is formulated from using the result of the other.

Newton's law of gravity had come after that Kepler's laws was formulated.

The law of gravity is more fundamental than Kepler's laws.

Newton formulated his famous law of gravitation between the earth and the moon and also between the Sun and the planet.

After that Kepler's laws came. He gave the law of orbit in which he said that the planet revolves the Sun in an eliiptical orbit. And the other two laws were also given by him. In this way Kepler's law was formulated by using the law of gravity.

Therefore, Kepler based his laws of planetary motions off of Newton’s law of gravity is the best example to show how scientific knowledge is cumulative.

Kepler based his laws of planetary motions off of Newton’s law of gravity.

What is the gravitational force acting on a 70.0 kg object standing on the earth's surface ?

Answers

g( gravitational acceleration)=-9.81 m/s^2
m(mass) = 70.0 kg

According to Newton's second law of motion:

"F=ma"

Force is equal mass per acceleration therefore

W=mg
This is because weigth is the force of gravity acting in a body and "a" is replaced by "g" because "g"
is gravitational acceleration

Therefore:

W= mg
W= (70.0 kg) (-9.81m/s^2)
W= -686.7 N

* The "N" means newton which is (kg* m/s^2)

Final answer:

The gravitational force acting on a 70.0 kg object on Earth is calculated using the formula w=mg and is equal to 686 N.

Explanation:

The gravitational force acting on a 70.0 kg object standing on the earth's surface can be calculated using the formula for weight (which is essentially the gravitational force on the object): w = mg, where m is the mass of the object and g is the acceleration due to gravity. On Earth, g is approximately 9.8 m/s².

Therefore, the gravitational force (weight) acting on this object can be calculated as follows: w = mg = (70.0 kg)(9.8 m/s²) = 686 N. Thus, the gravitational force on this 70.0 kg object standing on the earth's surface is 686 Newtons. It's important to understand that this force will vary if the object is moved to a location where g is different, like on the moon.

Learn more about Gravitational Force here:

brainly.com/question/32609171

#SPJ11

What is the "address" of the earth in the Cosmo

Answers

This inaugural journey may be slow-going for those who already know their way around the solar system, as our place in it is explained by a “cosmic address” (Earth, solar system, Milky Way, local group, Virgo supercluster, observable universe), but interest will be held by the sharp and mesmerizing graphics.

a gust of wind blows an apple from a tree. As the apple falls, the gravitational force on the apple is 2.25N downward and the force of the wind on the apple is 1.05N to the right. Find the magnitude and the direction of the net force on the apple.

Answers

Vertical component = 2.25 N downward

Horizontal component = 1.05 N to the right

Magnitude of the net force = √ (2.25² + 1.05²)
      = √6.165 = 2.483 N (rounded)

Direction of the net force = tan⁻¹ (1.05/2.25) to the right of downward

   = tan⁻¹ ( 7/15 ) to the right of downward

   = 25° to the right of downward (rounded)

The magnitude of the net force on the apple is $\boxed{2.48{\text{ N}}}$ .

The direction of the net force is with vertical $\boxed{25^\circ}$ .

Further explanation:

Here, we have to calculate the magnitude and the direction of the net force on the apple.

Given:

The gravitational force exerted on the apple is $2.25{\text{ N}}$ .

Force exerted by the wind on the apple is $1.05{\text{ N}}$ .

Formula and concept used:

The gravitational force is a universal force and it act in downward direction that is towards the center of the earth.

The direction of the force exerted by the wind on the apple is towards write side in the horizontal direction.

So, the angle between the gravitational force and force due to wind will be $90^\circ$ that is both the forces are perpendicular to each other.

Consider gravitational force is $W$ and force due to wind is $F$ .

So, the net force applied on the apple is,

$\boxed{R=\sqrt {\left( {{W^2} + {F^2} + 2WF\cos \theta } \right)} }$

Here, $\theta$ is the angle between both the forces which is equal to the $90^\circ$ .

So, the above equation can be written as,

$R=\sqrt {{W^2} + {F^2}}$ …… (1)

The direction of the net force can be written as,

$\boxed{\phi={{\tan }^( - 1)}\left( {(F)/(W)}\right)}$ ….. (2)

Calculation:

Substitute $2.25{\text{ N}}$ for $W$ and $1.05{\text{ N}}$ for $F$ in the equation (1).

$\begin{aligned}R&=\sqrt {{{2.25}^2}+{{1.05}^2}}\n&=\sqrt {6.165}\n&=2.48{\text{ N}}\n\end{gathered}$

For the direction,

Substitute $2.25{\text{ N}}$ for $W$ and $1.05{\text{ N}}$ for $F$ in the equation (2).

$\begin{aligned}\phi&={\tan ^( - 1)}\left( {\frac{{1.05}}{{2.25}}} \right)\n&=25^\circ\n\end{aligned}$

Thus, the net force on the apple is $\boxed{2.48{\text{ N}}}$ and direction of the net force is with vertical $\boxed{25^\circ}$ .

Learn more:

1. Water is a compound: brainly.com/question/1073452

2. Expansion of the gas with change in temperature: brainly.com/question/9979757

3. Two arrows are fired simultaneously with the speed of 30m/s brainly.com/question/2370982

Answer detail:

Grade: Senior School

Subject: Physics

Chapter: Force

Keywords:

Wind blow, apple falls, gravitational force, wind force, magnitude of force, direction of force, 2.25N downward, 1.05N, magnitude and direction, net force on apple.

What is a Vector and a scalar?

Answers

Scalars are quantities that are fully described by a magnitude (or numerical value) alone.
Vectors are quantities that are fully described by both a magnitude and a direction.

How to do this problem

Answers

Answer:

v = 12,4 m/s

Explanation:

frictionless means all gravitational Energie (Eg) will be converted to kinetic Energie (Ek)

Ek = 0.5 * m * v^2

Ez = m * g * h

Ek = Ez

0.5 * m * v^2 = m * g * h

divide left and right of the = sign by m.

(This means that the final velocity is independent of the mass of both children !)

0.5 * v^2 = g * h

v^2 = 2 * g * h

v = +- SQRT (2 * g * h)

with

g = 9.8 m/s^2

h = 7,8 m/s

v = +- SQRT (2 * 9.8 * 7.8)

v = +- SQRT (152.88)

(v = - 12,4 m/s has no meaning in this case)

The velocity 7,8 m below the starting point, will be

v = 12,4 m/s

Answer:

the answer is 336.96 mph

Explanation:

hope this helps ^_~

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