The grams of calcium phosphate that can be produced when 89.3 grams of calcium chloride reacted with excess sodium phosphate is
83.08 grams of calcium phosphate
calculation
Step 1: write a balanced chemical equation
3CaCl₂ + 2Na₃Po₄ →6NaCl + Ca₃(PO₄)₂
step 2: find the moles of CaCl₂
moles = mass÷ molar mass
from periodic table the molar mass of CaCl₂ = 40 +( 2 x 35.5) =111 g/mol
moles = 89.3 g÷111 g/mol = 0.805 moles
Step 3: use the mole ratio to determine the moles of Ca₃(PO₄)₂
CaCl₂: Ca₃(PO₄)₂ is 3:1 therefore the moles of Ca₃(PO₄)₂ =0.805 x 1/3 =0.268 moles
Step 4: find mass of Ca₃(PO₄)₂
mass = moles x molar mass
from periodic table the molar mass of Ca₃(PO₄)₂ = (40 x3) +[ 31 +(16 x4)]2 =310 g/mol
mass is therefore =0.268 moles x 310 g/mol =83.08 grams
Answer:
about 200 calories of heat must be added to 1 gram of ethanol to convert it from a liquid to a gas
Explanation:
Answer:
I got you..you need help but with which question?
Explanation:
Have a great day!
Answer:
4.88 kg
Explanation:
Amount of energy generated in 1 hour of exercise = 5500 kJ
Thus,
Amount of energy generated in 2 hours of exercise = 5500*2 kJ
So,
Amount of energy generated in 2 hours of exercise = 11000 kJ
Heat of vaporization of water = 40.6 kJ/mol
40.6 kJ of energy is required to vaporize 1 mole of water
Also,
11000 kJ of energy is required to vaporize (1/40.6) * 11000 mole of water
Moles of water = 270.936 moles
Molar mass of water = 18 g/mol
Mass = Moles * Molar mass = 270.936 * 18 g = 4876.8473 g
Also,
1 g = 0.001 kg
So, mass of water = 4.88 kg