A student pushes a box across a rough horizontal floor. If the amount of work done by the student on the box is 100 J and the amount of energy dissipated by friction is 40 J, what is the change in kinetic energy of the box

Answers

Answer 1

Answer:

Answer:

60J

Explanation:

friction is the opposition to the motion of an object. Before a body can be set in motion, part of the energy or work-done must be used to overcome friction.

While kinetic energy is the energy associated with a body due to its motion.

Since friction tends to oppose the motion of a body,when a body start to move, some of the energy applied to the body to cause its motion is converted to heat due to friction.

Hence if a work-done of 100J is applied to a body that requires 40J of the work to overcome friction, the total change in the kinetic energy can be expressed as

$K.E=100J-40J\nK.E=60J\n$

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What happens to the gravitational force between two objects when their distance is changed?

Answers

If they become closer, it is increased, and if the objects become farther away is decreased.

The sun is its highest in the sky during what season

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*olaf voice*

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A body moving with a velocity of 20m/s begins to accelerate at 3 m/s 2 . How far does the body move in 3 seconds

Answers

Given v_in = 20 m/s and a = 3 m/s2, assuming that the bodymoves at constant acceleration, the motion is modeled by the equation:

s(t) = (v_in)t + (1/2)a(t^2)

where s(t) is the distance traveled

substituting the given,

s(t) = 20t + (3/2)(t^2)

at t = 3

s(t) = 20(3) + (3/2)(3)^2

= 73.5 m

Why is chlorine bonded by a single covalent bond, but Oxygen bonded by a double covalent bond?

Answers

Answer:

chlorine is a non-metal.

Explanation:

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What is the most current NASA mission on Mars?

Answers

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15) What is the frequency of a pendulum that is moving at 30 m/s with a wavelength of .35 m?show step by step

Answers

We know that there is a formula velocity = frequency x wavelength for all types of waves.

If we assume one complete oscillation of a pendulum to be wavelength we can apply the above formula for the pendulum too.

So as v = fλ and f = v/λ we can just plug in the values to get our answer of frequency.

So frequency = 30/0.35 which is equal to 85.17 Hertz (Hz).

I think you're trying to take the formulas for speed, wavelength, and
frequency of a wave, and apply them to a pendulum. You can't do that.
It doesn't work.

A pendulum is moving in 'simple harmonic motion', not wave motion.
It's speed is continuously changing, from zero at both ends of its swing,
to maximum as it passes through the 'rest' position at the bottom. And
there's no wavelength defined for a pendulum ... if you're thinking that
it could be the distance from end to end of its swing, or maybe half of
that, you should know that the frequency of an ideal simple pendulum
is not related to that distance at all.

Finally, in the real world, the numbers in this question really kind of
don't make any sense. You have a structure where some part of it is
roughly a foot long (0.35m = 13.8 inches), and at least at some point
during its swing, something is moving at 30 m/s ... about 67 mph !
If something like that could even stay on the table, and IF its frequency
were (speed/wavelength) ... like a wave's frequency is ... then its frequency
would be (30 / 0.35) = 85.7 Hz ! ! The thing would be wiggling back and
forth every 0.017 second ! It would need to be operated only inside
a bomb shelter, with all personnel withdrawn beyond a safe perimeter
before it flies apart and scatters shrapnel everywhere.

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