Sunglass World marks up its designer sunglasses 220%. The manufacturer charged Sunglass World $14.33 for a specific brand and model. What is the selling price of that pair of sunglasses at Sunglass World?
Answers
The selling price is $31.53
Related Questions
Which is a third degree polynomial with -3 and 2 as its only zeros?a. f(x)=x^3+x^2-8x-12b. f(x)=x^3+2x^2-5x-6c. f(x)=x^3+4x^2-3x-18d. f(x)=x^2+x-6
Mrs Thomas played a game. Her score changed the same amount each round. After 3 rounds, her score had changed by -18 points. How much did her score change during each round?
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Is 3(2)^x equivalent to 1.5(2^x)(2^1)
Answers
Answer:
18.75%
Step-by-step explanation:
The probability of the coin is 1/2, because it only has two options (tail or head).
Now, in the case of roulette, it has a total of 8 options, and the red region has 3 parts, that is, of the 8 options, roulette 3 is red, therefore the probability is 3/8
Now the final probability is the multiplication of the probability of both events:
(1/2) * (3/8) = 0.1875s 18.75%
In other words, the probability of these two events happening, that the tail comes out and is red, i
5 % pay raise, this year's salary is
$34,125.
Answers
As a percentage, last year's salary was 100%
After a 5 percent raise, the new salary is 105%;
The 105% is equivalent to 34,125;
The older salary was;
=
= 32,500 dollars
(i think its 0.142)
Answers
Answers
FOR EXAMPLE:
$1 and $2.75
You would ignore dollar sign and add together like normal to get
3.75
But remember to add dollar sign back at the end.
If the value only have 2 values with cents it should be something like
0.54 cents BUT NO DOLLAR SIGN
Hope that helps
Answers
Answers
Laʀc = (2πR) • (θ ⁄ 2π) = R • θ ... where θ = central angle (of sector)
Ps = R + R + (R • θ) ... perimeter of sector = Ps
Ps = R • (2 + θ) ... Ps = 100 ft
100 = R • (2 + θ)
θ = (100 ⁄ R) – 2
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~...
Similarly, the sector area is just a fraction of the circle area:
As = (πR²) • (θ ⁄ 2π) ... area of sector = As
As = R² • θ ⁄ 2 ... substitute for θ
As = R² • [(100 ⁄ R) – 2 ] ⁄ 2
As = 50R – R² ... differentiate
As' = 50 – 2R ... set to zero
0 = 50 – 2R
R = 25 ft ... optimum radius
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~...
As = 50R – R² ... evaluate at: R = 25 ft
As = 50(25) – (25)²
As = 625 ft² ... maximum area
Note ... at any other R_value, the sector area is less.
" θ " can be determined using: θ = (100 ⁄ R) – 2
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Final answer:
For a circular sector with a fixed perimeter of 100 ft, the values of radius (r) and arc length (s) that will maximize the sector's area are r=25 and s=50.
Explanation:
The perimeter of a circular sector is composed by the length of the arc (s) plus twice the radius (r). If this sum is fixed at 100 ft, then the length of the arc s is equal to 100 - 2r. The area A of a circular sector can be defined as A = 0.5 * r * s.
Substituting the expression for s into the area formula obtains A = 0.5 * r * (100-2r). Simplifying results in A = 50r - r^2 which is a downward opening parabola.
The maximum value of a parabola occurs at the vertex. For a parabola in the form y=ax^2 + bx + c, the x-coordinate of the vertex is -b/(2a). In this case, a=-1 and b=50, hence r=-50/2*(-1) = 25. Substituting r=25 back into the formula for s obtains s = 100-2*25 = 50. Therefore, the values for r and s that will give the circular sector the greatest area are r=25 and s=50.
Learn more about Perimeters and Areas here:
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