Answers
Answer:
The correct answer is e. All of the above.
Explanation:
Sister chromatids are made during the synthesis phase of the cell cycle. In the synthesis phase, the homologous chromosomes get replicated and sister chromatids are produced so they are produced by duplication of chromosomes.
As sister chromatids are produced by replication, therefore, they are identical copies of parent chromosomes. These sister chromatids are joined to each other at centromere. They get separated during the anaphase of mitosis and moves to the opposite pole.
Therefore the right answer is e.
Related Questions
ATP hydrolysis _______.to ADP and Pi is the most common mechanism for transferring free energy to drive endergonic reactionswould be more exergonic if phosphate did not have resonance structuresresults in products that are less solvated than the ATPis usually in the form of ATP -> ADP Pi or ATP -> AMP PPi
Which statements accurately describe the structure of the cell membrane? Check all that apply. The cell membrane is a single layer of phosphate molecules and lipids. The cell membrane is a double layer of phosphate molecules and lipids. The cell membrane has protein channels that are partly inside and partly outside the cell. The cell membrane has protein channels that are entirely inside the cell. The cell membrane’s protein channels only let certain molecules pass through. The cell membrane’s protein channels let all molecules pass through.
Proteins accomplish many cellular tasks such as facilitating chemical reactions, providing structure, and carrying information from one cell to another. How a protein chain coils up and folds determines its three-dimensional shape. Its shape will, in turn, determine how it interacts with other molecules and thus performs its function in the cell.
7. Some plants make cones. Other plants make flowers. What is the purpose of flowers and cones?A. They move water and food throughout the plant.B. They hold the plant and soil so that it does not blow over in heavy winds.C. They make seeds so that the plant can reproduce.D. They take in water and nutrients from the soil.
Answers
Explanation:
Plants in forest are not supplied with fertilizer by human beings ,yet they get mineral and salt from the dead decaying body of plants and animal found in the forest .Animal die in forest get converted into humus by bacteria and other animals .Sources of energy is transferred from one life to other by different means in this way plants in forest get plant and mineral.
Answers
Answer:
chloroplasts
Explanation:
Final answer:
Among the listed organelles, chloroplasts cannot be found in an animal cell. Instead, chloroplasts are present in plant cells and certain algae, playing a key role in the process of photosynthesis. The other organelles - ribosomes, lysosomes, and vacuoles - are all present in animal cells.
Explanation:
Among the options listed - chloroplast, ribosome, lysosome, and vacuole - the one that cannot be found in an animal cell is the chloroplast. Chloroplasts are organelles present in plant cells and certain algae. They play a critical role in a process called photosynthesis, during which sunlight, water, and carbon dioxide are converted into oxygen and glucose. However, animal cells do not have chloroplasts because they do not perform photosynthesis. Instead, they obtain energy via different processes such as cellular respiration, which happens in mitochondria. On the other hand, ribosomes, lysosomes, and vacuoles are indeed present in animal cells. Ribosomes are involved in the synthesis of proteins, lysosomes handle waste disposal and cellular digestion, and vacuoles are involved in storing substances and maintaining turgor pressure within the cell.
Learn more about Organelles here:
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Why do you think this is happening? (Things
to think about: habitat destruction, erosion,
pollution, invasive species, human impact.)
Answers
Answer:
Well the most common is habittat destruction. With the number of humans only growing, more land is needed and habitat desturctions occur. Lack of food is also a problem, as some crops don’t grow as much so the bee’s food source is smaller which leaves thousands dead. Also if the food source doesn’t run out, there are pesticides sprayed and the bees will die if eaten one which the chemical properties in a pesticide will kill. Also if not used, littering, if you dump it into a water source, the water gets contaminated and the bees could die from that, or the water spreads ano the flower would receive this chemical property, which could kill the Bee’s food source, or the flower doesn’t die but when the bees consume it, the bee will die.
Answer:
honey bees Extinction types are parasites ,habitat loss ,and cell phones. but there two main types of parasites that are harming the honeybees are Vero mites and tracheal
Answers
Answer:
RNA was the genetic material
Explanation:
If avary, Macleod, and McCarty would have seen that only RNAse treatment of the heat-killed bacteria prevented the transformation of genetic virulence than might have concluded that RNA is the genetic material as transformation does not occur because the RNAase degraded the RNA.
But if the genetic material is DNA then RNAase will not work because RNAase can not degrade DNA and then DNA will pass from virulent heat killed strain to nonvirulent strain and will cause transformation.
Answers
Answer:
11.7 g in 1 L of water.
Explanation:
Molarity (M) or Molar concentration is a measure used in chemistry for solutes in a solution.
It is defined as mol/ L (number of moles per litre).
0,2 M means we have 0,2 mol/ L
In order to know how many grams this means we need to look up the molecular weight of the solute. In this case NaCl: 58.443 g/mol
=
X=
X= 11.69 g
The solution has 11.69 g of NaCl in 1 L of water since its an adequate polar solvent for NaCl dissolution.
Answers
Answer:
The population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.
Explanation:
From the given information:
For food source A; we have:
3P₁ + P₂ + 2P₃ = 58 units of food A ---- (1)
For food source B; we have:
2P₁ + 4P₂ + 2P₃ = 70 units of food B ---- (2)
For food source C; we have:
P₁ + P₂ = 20 units of food C ----- (3)
From equation (1) and (2); we have:
3P₁ + P₂ + 2P₃ = 58
2P₁ + 4P₂ + 2P₃ = 70
By elimination method
3P₁ + P₂ + 2P₃ = 58
-
2P₁ + 4P₂ + 2P₃ = 70
P₁ - 3P₂ + 0 = - 12
P₁ = -12 + 3P₂ ---- (4)
Replace, the value of P₁ in (4) into equation (3)
P₁ + P₂ = 20
-12 + 3P₂ + P₂ = 20
4P₂ = 20 + 12
4P₂ = 32
P₂ = 32/4
P₂ = 8
From equation (3) again;
P₁ + P₂ = 20
P₁ + 8 = 20
P₁ = 20 - 8
P₁ = 12
To find P₃; replace the value of P₁ and P₂ into (1)
3P₁ + P₂ + 2P₃ = 58
3(12) + 8 + 2P₃ = 58
36 + 8 + 2P₃ = 58
2P₃ = 58 - 36 -8
2P₃ = 14
P₃ = 14/2
P₃ = 7
Thus, the population of each bacteria in 1, 2, 3 are 12, 8, and 7 respectively.