There were 480 people at play. The admission price was $2 for adults and $1 for children. The admission receipts were $770. How many adults and how many children attended?

Answer:

290 adults and 190 children attended the Play.

Step-by-step explanation:

Given:

Total number of people in play = 480

Let the number of adults be x

and Number of children be y

Hence we can write the equation as;

Also Given:

Price for 1 adult = $2

Price for 1 children = $1

Total admission receipts = $770

Hence we can write the equation as;

Now We will subtract equation 1 from equation 2 we get;

Now substituting the value of x in equation 1 we get;

Hence 290 adults and 190 children attended the Play.

Final answer:

The problem is solved by creating two equations based on the given information and solving the system of equations to find that there were 290 adults and 190 children who attended the play.

Explanation:

To solve the problem of determining how many adults and children attended the play, we need to set up a system of equations.

Let A be the number of adults and C be the number of children who attended the play. We are given two pieces of information:
The total number of people at the play was 480, which gives us the equation A + C = 480.

The total amount of money collected from admissions was $770. Since adults pay $2 and children pay $1, the equation is 2A + C = 770.

Now we have a system of two equations:
A + C = 480

2A + C = 770

To solve this system, we can subtract the first equation from the second equation to eliminate C:

2A + C - (A + C) = 770 - 480

which simplifies to:

A = 290

Now, plug A = 290 into the first equation to find C:

290 + C = 480

Subtract 290 from both sides:

C = 190

So, there were 290 adults and 190 children at the play.

Learn more about system of equations here:

brainly.com/question/21620502

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