Answer:
D. 1/12 is the answer
Step-by-step explanation:
the probability of rolling a 4 is 1/6, and the probability of flipping tails is 1/2. If you multiply 1/2 and 1/6 you get 1/12.
Step-by-step explanation:
The question is not well written. Let us say the function given as expressed as;
f(x) = -1/x + 3/x⁴
f'(x) means we are to differentiate the function with respect to x;
Given f(x) = axⁿ
f'(x) = naxⁿ⁻¹
f(x) = -x⁻¹ + 3x⁻⁴
Applying the differentiation formula we will have;
f'(x) = -1(-x⁻²)+(-4)3x⁻⁴⁻¹
f'(x) = x⁻²-12x⁻⁵
Express as a fraction
f'(x) = 1/x²-12/x⁵
To get f'(4), we will have to substitute x = 4 into the resulting expression
f'(4) = 1/4²-12/4(5)
f'(4) = 1/16-12/20
f'(4) = 1/16-3/5
Find the LCM
f'(4) = (5-48)/80
f'(4) = -43/80
Note that the function used was assumed but the same method can be employed to any other functions.
how do you solve this?
Answer:
Step-by-step explanation:
Given: Data is in terms of rainfall (in inches) and Yield of wheat (bushels
per acre)
Equation of Best fit line for 9 year of data is Y = 47.3 + 0.78X
To find: Bushels of wheat per acre when 17 inches of rain expected.
Given problem is of Regression analysis as we are given with best fit line.
From the Equation of Best fir line we can conclude that it is equation of line Y on X because when put value of X we get value of Y.
From Given Data, let say X be Rainfall length and Y be Yield of wheat.
So, to find the Bushels of wheat (yield) when 17 inches of rainfall is expected.
we put value X = 17 in given equation.
⇒ Y = 47.3 + 0.78 × ( 17 )
⇒ Y = 47.3 + 13.26
⇒ Y = 60.56
Therefore, 60.56 bushels of wheat per acre can be predicted if 17 inches of rain is expected.
Answer:
and
Step-by-step explanation:
Let x be the altitude of a commercial aircraft
=>The expression " A minimum altitude of 29,000 feet" is equal to
All real numbers greater than or equal to 29,000 ft
=>The expression " A maximum altitude of 41,000 feet" is equal to
All real numbers less than or equal to 41,000 ft
therefore, The compound inequality is equal to
and
All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft
The solution is the interval [29,000,41,000]