MATHEMATICS HIGH SCHOOL

Round this number to the nearest hundred.
728

Answers

Answer 1
Answer: 700 is the answer......

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Write as an algebraic expression and simplify if possible: *150% of 50% of z whoever answers the fastest gets brainliest
If you print the residuals for StudentSurvey.modelGPA, what will you see?A) 3.158 B) for each participant in the study, the difference between his/her GPA and the mean GPA C) for each participant in the study, the model (i.e. the mean) for GPA D) the GPA of each participant in the study

Find the gradient and intercept of the line y=9x-1

Answers

This equation is in slope-intercept form,so 9x = slope and -1 = y-intercept.
9x= slope and -y=y intercept

If you are conducting a survey on students' awareness of traffic laws, which question is most relevant to your study? A. Do you lend your car to your friends?B. Do you listen to the radio while driving?C. Do you have a driver's license?D. How often do you take your car in for maintenance?

Answers

the answer is C due to the fact that it correlates directly to the question since you can determine the level of traffic law awareness if the person has or doesn't have a license
Definitially C since no orther question effects their knowledge

6x + 1 = -6(1-x) please show work i need what is x

Answers

Answer:

Step-by-step explanation:

6x+1=-6(1-x)

6x+1=-6+6x

6x+7=6x

7=0

no solution

THERE'S TOO MUCH CATFISHES ON THIS SITE

Answers

Answer:

what do you mean by that?

Step-by-step explanation:

A rectangle measures fourteen centimetrers by four centimetres what is its area

Answers

The formula for finding the area of a rectangle is:
\sf area = length * width

Here we are given that the length is 14 cm, and the width is 4 cm.

So the are will be:

\sf area = 14~cm * 4~cm\n\n\boxed{\sf{area = 56 cm^2}}
The rectangles area is 56 cm. messed it up the first time!! lol

Pls help with these questions, u don’t have to do both but it will help if u do :D thankss (will give brainliest)

Answers

To find the length of the sides of the isosceles triangle with vertices at A(1, -2), B(-5, 2), and C(2, 6), we need to calculate the distances between the points.

Let's first find the distance between points A and B:

Distance AB = √[(x2 - x1)^2 + (y2 - y1)^2]
Distance AB = √[(-5 - 1)^2 + (2 - (-2))^2]
Distance AB = √[(-6)^2 + (4)^2]
Distance AB = √[36 + 16]
Distance AB = √52 ≈ 7.21 (rounded to 2 decimal places)

Next, let's find the distance between points B and C:

Distance BC = √[(x2 - x1)^2 + (y2 - y1)^2]
Distance BC = √[(2 - (-5))^2 + (6 - 2)^2]
Distance BC = √[(7)^2 + (4)^2]
Distance BC = √[49 + 16]
Distance BC = √65 ≈ 8.06 (rounded to 2 decimal places)

Finally, let's find the distance between points C and A:

Distance CA = √[(x2 - x1)^2 + (y2 - y1)^2]
Distance CA = √[(1 - 2)^2 + (-2 - 6)^2]
Distance CA = √[(-1)^2 + (-8)^2]
Distance CA = √[1 + 64]
Distance CA = √65 ≈ 8.06 (rounded to 2 decimal places)

Since the isosceles triangle has two sides with the same length, the length of these sides is approximately 8.06 units (rounded to 2 decimal places).

To find the coordinates of the point where the line 2x + y = 11 crosses the x-axis, we need to set y to 0 and solve for x.

When y = 0, the equation becomes:

2x + 0 = 11

Now, isolate x:

2x = 11

x = 11 / 2

x = 5.5

So, the point where the line crosses the x-axis has coordinates (5.5, 0).
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