Given 2 points on a graph, write the equation of the graph. Vertex (3,5). Point(5, -3)

Answers

Answer 1

Answer: we know that
for
y=a(x-h)^2+k
vertex is (h,k)
given vertex is (3,5)
y=a(x-3)^2+5
we are also given
(5,-3)
x=5 and y=-3 is a possible solution

-3=a(5-3)^2+5
-3=a(2)^2+5
minus 5 both sides
-8=a(4)
-8=4a
divide by 4 both sides
-2=a

the equation is
$y=-2(x-3)^2+5$

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Show your working for the following questions:-18 divided by -3

Two sevenths times eight thirds

Three eights plus one twelth

Answers

$(-18)/(-3)$ (divide 3 from numerator and denominator) = $(6)/(1) = 6$

$(2)/(7)$ × $(8)/(3)$ = $(16)/(21)$

$(3)/(8) + (1)/(12) = (9)/(24) + (2)/(24) = (11)/(24)$

Which phrases correctly describe the location of –34 on the number line?

Choose exactly two answers that are correct. A. to the right of –21 B. to the left of –63 C. to the left of –28 D. to the right of –35

Answers

A is wrong because -34 would be on the left of -21.

B is also wrong because -34 would be to the right of -63.

C is correct because -34 is to the left of -28

D is also correct because -34 is to the right of -35.

A baseball player had 4 hits in 8 games. At this rafe, how many hits will the baseball player have in the next 28 games?

Answers

Answer: About 14 hits

Danna says that even numbers are the composite is she right

Answers

Answer:

all even numbers except 2 are composite numbers !

Step-by-step explanation:

no need for explanation

Rosie works 40 hours a week as an office manager. If she made $23,920 last year, how much was she paid per hour?

Answers

Hey there..
Lets solve this questions in steps..

Step 1 - we need to know that how many weeks are there in 1 year
so, there are 52.17 weeks but the round figure is 52 weeks.

Step 2 - we know that shawn worked 40 hours a week
So, in order to get total hour worked by him in one year, we need to multiply 52 * 40
i.e. 52 *40 = 2080

Step 3 - Now, we have total hours we can simply divide the total hour worked with how much he earned last year
i.e. 23,920 / 2080
= $11.5 per hour.

Hope this helped you.. :)

Answer:

11.50

Step-by-step explanation:

Find all zeros (both real and complex) for the function f(x)=x^3-5x^2+4x+10

Answers

$f(x)=x^3-5x^2+4x+10\n f(x)=x^3+x^2-6x^2-6x+10x+10\n f(x)=x^2(x+1)-6x(x+1)+10(x+1)\n f(x)=(x+1)(x^2-6x+10)\n\n x+1=0\n x=-1\n\n x^2-6x+10=0\n x^2-6x+9+1=0\n (x-3)^2=-1\n x-3=i \vee x-3=-i\n x=3+i \vee x=3-i\n\n x=\{-1,3-i,3+i\}$

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