The velocity of a 500-kilogram elevator that has 4,000 joules of energy is 4m/s.
KINETIC ENERGY:
K.E = ½m.v²
Where;
m = mass of the elevator (kg)
v = velocity of the elevator (m/s)
V = √K.E × 2/m
V = √4000 × 2/500
V = √8000/500
V = √16
V = 4m/s
Learn more: brainly.com/question/10703928?referrer=searchResults
Answer:
-5 m/s
Explanation:
vo = 10 m/s
a = -1 m/s²
t = 15 s
v = vo + at
= 10 + (-1)(15)
= -5 m/s
(actually the train has come to a stop at t = 10s)
B movable
C combination
D advantageous