MATHEMATICS HIGH SCHOOL

Which rule represents the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I'?(x, y)→(x - 8, y - 7)

(x, y)→(x - 7, x - 8)

(x, y)→(x - 4, x - 5)

(x, y)→(x - 5, y - 4)

(adding picture in a second)

Answers

Answer 1
Answer: We will choose two vertices of hexagon DEFGHI and hexagon D´E´F´G´H´I´:
D ( 2, 5 )  → D´( - 6 - 2 )
E ( 5, 5 )  → E ´( - 3. - 2 )
- 6 = 2 - 8,      - 2 = 5 - 7
- 3 = 5 - 8,      - 2 = 5 - 7
Answer: A) ( x, y )→ ( x-8,  y-7 )
Answer 2
Answer:

Answer:

A. (x, y)→(x − 8, y − 7)

Step-by-step explanation:

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Can you help me can you help me ​

Answers

Answer: a

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Answer:

The mountain has a base 150 feet above sea level.

Jim climbs 233 feet

150 + 233 = 383 feet above sea level.

After that, he descends x feet, but the picture is cropped.

How do you write the standard number 0.000068 in scientific notation?6.8 × 10-4
6.8 × 10-5
6.8 × 10-7
6.8 × 10-6

Answers

6.8 * 1--5 or also known as the second answer.

Students who work ____ or more hours per week have average lower GPAs than students who work ____ or fewer hours per week.

Answers

Answer: Ultimately, the number of hours a student works can impact their GPA, and it is generally advisable for students to limit their work hours to ensure they have enough time and energy to focus on their studies and perform at their best.

Step-by-step explanation:

What is the midpoint of (-12,0) and (-3,0)?

Answers

The midpoint is (-15/2,0)

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park. Write and solve an equation to find how far Joey walked to get to Armando's home.

Answers

Let's start by assuming Armando's house is between Joey's and the park. 

Let x be the distance Joey walked to Armando's house.

The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park. 

(9)/(10) = x + (3)/(5)

x = (9)/(10) - (3)/(5) = (9)/(10) -(6)/(10) = (3)/(10)

That's probably the answer they're looking for.  But what if the park is between Joey and Armando's houses or Joey is between the park and Armando?  (The latter isn't really possible with the given distances.)

Let a, b, c be the distances between three collinear points like we have here.  Our equation is really a few equations in one, something like

\pm a \pm b = \pm c

Let's get rid of the plus/minuses. Squaring,

a^2 + b^2\pm 2ab = c^2

\pm 2ab = c^2-a^2-b^2

4a^2b^2 = (c^2-a^2-b^2)^2

For us, that's a quadratic equation for c^2

4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2

I'll skip right to the solutions,

c^2=(9)/(100) \textrm{ or } c^2=(9)/(4)


c=(3)/(10) \textrm{ or } c=(3)/(2)

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

The beginning inventory at cost is $80,000.00 and at retail is $100,000.00. Purchases at cost are $160,000.00 and the retail value is $200,000.00. Net sales are $250,000.00. The ending inventory at cost isA. $240,000
B. $50,000.00
C. $40,000
D. $192,000

Answers

Cost of goods available for is equal

80000+160000=240000

Retail value is equal

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This means that the cost of goods sold is 80% (240000÷300000) and gross profit is 20%


Sales= 250000 and it's cost is equal 200000 (250000×0.8)


Ending inventory

=240000-200000=40000...answer


Hope it helps!

Answer:

$40,000

Step-by-step explanation:
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