Answer:
There are so many ways! Do want me to help?
Step-by-step explanation:
Answer:
1/8
Step-by-step explanation:
Tommy: 3/8
Joel: 4/8
Garrett: 1/8
B)h(t) = (-16t2 + 3)/2
C)h(t) = -16(t/2)2 + 3
D)h(t) = -8(t)2 + 3
The correct function that describes the height of the ball on a replay that runs at half speed is h(t) = -16(t/2)^2 + 3. This is because the time in the original function enters as a square, so it must be halved before being squared.
In this problem, a slow motion replay means the time factor is slowed down by a half. The original function is h(t) = -16t2 + 3. However, the time factor isn't just halved, it's halved before being squared, because time enters the function as a square. So in the replay function, every instance of t in the original function is replaced with 0.5t or t/2. Hence, the correct option that describes the height of the ball in the replay is h(t) = -16(t/2)2 + 3.
#SPJ11