Answer:
Let {A, B, C, D} be the set of boxes of regular sodas and {a, b, c, d} be the set of boxes of diet sodas. Denote the numbers of combinations of M boxes taken P boxes. Note that the specific combination, for example, AB from the set of boxes of regular sodas is the same as the combination BA. The number of ways to pick 2 boxes from each category is . Hence, the number of ways of picking 4 boxes in which he pick 2 boxes from each category is * = 6*6 = 36.
A.1 over 20
B.3 over 64
C.7 over 16
D.9 over 16
Answer:
7/16
Step-by-step explanation:
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2. Identify the independent and dependent quantity.
3. The domain and range are represented as discrete or continuous?
4.What is a reasonable domain and range for this scenario?
Thanks for the help!
Answer:
1) M(x) = 5 + 3x
2) Dependent variable; 3 dollar bills
Independent variable: chores
3) Range is continuous
Domain is discrete
4) Range: 0 ≤ x ≤ 10
Domain: 5 ≤ M ≤ 35
Step-by-step explanation:
We are told he started with 5 number of $1 dollar bills and that every Saturday, he earns 3 more $1 dollar bill.
Thus, total number of $1 bills earned after x number of Saturdays(weekly) is;
M(x) = 5 + 3x
After 10 weeks, total number is;
M(10) = 5 + 3(10)
M(10) = 35
The dependent variable is the 3 more dollar bills earned each Saturday because it depends on chores he completed. While the independent variable is the chores because it doesn't depend on anything.
After 10 weeks, the range and domain will be;
Range: 0 ≤ x ≤ 10
For the; Domain:
For x = 1, M(0) = 5 + 3(0) = 5
M(10) = 35
Thus;
Domain: 5 ≤ M ≤ 35
The range could be all numbers in the interval from 0 to 10. Thus, it is continuous.
Whereas, the domain doesn't contain all the numbers in the interval from 5 to 35. Thus it is Discrete.
Answer:
.
Step-by-step explanation:
2,500 g, 250 kg
3.4 kg, 3,400 g
480 g, 4.8 mg
Answer:
Step-by-step explanation:
To express "twice the difference of a number and 5" algebraically, we can follow these steps:
Step 1: Let's represent the unknown number as 'x'.
Step 2: The difference of a number and 5 is obtained by subtracting 5 from the number, which gives us 'x - 5'.
Step 3: To find "twice the difference," we multiply the difference by 2, resulting in '2(x - 5)'.
Therefore, "twice the difference of a number and 5" can be expressed algebraically as '2(x - 5)'.