Answer:
Osa
Step-by-step explanation:
Relative distances
Osa is in a submarine 200 feet under sea level. We can say its distance to sea level is 200 feet
Jill is 311 feet above sea level, her distance to sea level is 311 feet
We can say Osa is closest to sea level
If we consider ground level to the reference where distances are measured from above, then we must say Osa is closest to it because she is below sea level and naturally, closer to the ground below it
Answer:
x =-2 and z =-4
Step-by-step explanation:
We need to solve the following systems of equation
-3x-2y+4z = -16 eq(1)
10x+10y-5z = 30 eq(2)
5x+7y+8z = -21 eq(3)
Multiply eq(1) with 10 and eq(2) with 3
-30x-20y+40z = -160
30x+30y-15z = 90
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10y+25z = -70
Divide by 10
2y+5z = -14 eq(4)
Multiply eq(1) with 10 and eq(3) with 6
-30x-20y+40z = -160
30x+42y+48z = -126
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22y+88z = -286
Divide by 11
2y+8z = -26 eq(5)
Subtract eq(4) and eq(5)
2y+5z = -14
2y+8z = -26
- - +
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-3z = 12
z = 12/-3
z = -4
Putting value of z in eq(4)
2y+5z = -14
2y +5(-4) = -14
2y = -14 +20
2y = 6
y = 3
Putting value of z and y in eq(1)
-3x-2y+4z = -16
-3x-2(3)+4(-4) = -16
-3x -6 -16 = -16
-3x = -16+16+6
-3x = 6
x = 6/-3
x = -2
B. 3×-12+6×+9