The velocity a stroller is pushed from rest, accelerating at 500m/s is 7.5 m/s.
To find the final velocity of the stroller after it has traveled a certain distance while accelerating, one can calculate it using the third equation of motion:
v²-u² = 2as
The third equation of motion is one of the equations used in classical physics to describe the motion of an object with constant acceleration.
Given:
Acceleration, a = 500 m/s²
Distance, s = 6.32 m
The velocity is computed as:
v² - 0² = 2 × 500 × 6.32
v² = 6320
v = 79.5 m/s
Hence, the velocity a stroller is pushed from rest, accelerating at 500m/s is 7.5 m/s.
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(1%, 0.9%) simplest answer
the answer is 11 km/h ... i just took the test
Answer:
50.5°C
Explanation:
Start with the ideal gas law:
PV = nRT
Rearranging:
P/T = nR/V
Since the right side is constant (volume and mass don't change):
P₁ / T₁ = P₂ / T₂
This equation is also known as Gay-Lussac's law. Plugging in the values (make sure to use absolute pressure and temperature):
(32 psi + 14.7 psi) / (25 + 273.15) K = (36 psi + 14.7 psi) / T
Solving for T:
T = 323.69 K
T = 50.5°C
b. amps/division
c. seconds/division
d. ohms/divisionthe horizontal sweep of an oscilloscope is rated in seconds/division.
Answer:
Second division
Explanation: