In summary, a line is perpendicular to x + 3y = -3 if its slope is 3.
The subject requested is about finding the slope of a line that is perpendicular to the line specified by the equation x + 3y = -3. To find the slope, we'll first have to rewrite the given equation in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.
Rewriting x + 3y = -3, we get y = -x/3 - 1. So the slope of the given line is -1/3. Now, two lines are perpendicular if and only if the product of their slopes is -1. Therefore, the slope of the line perpendicular to the given line will be -1 / original slope = -1 / (-1/3) = 3.
Thus, the slope of a line perpendicular to the line x + 3y = -3 is 3.
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Find the area of the figure. Round to the nearest tenth if necessary.
Step-by-step explanation: