Consider an unreliable communication channel that can successfully send a message with probability 1/2, or otherwise, the message is lost with probability 1/2. How many times do we need to transmit the message over this unreliable channel so that with probability 63/64 the message is received at least once? Explain your answer. Hint: treat this as a Bernoulli process with a probability of success 1/2. The question is equivalent to: how many times do you have to try until you get at least one success?

Answers

Answer 1
Answer:

Answer:

6 times we need to transmit the message over this unreliable channel so that with probability 63/64.

Step-by-step explanation:

Consider the provided information.

Let x is the number of times massage received.

It is given that the probability of successfully is 1/2.

Thus p = 1/2 and q = 1/2

We want the number of times do we need to transmit the message over this unreliable channel so that with probability 63/64 the message is received at least once.

According to the binomial distribution:

P(X=x)=(n!)/(r!(n-r)!)p^rq^(n-r)

We want message is received at least once. This can be written as:

P(X\geq 1)=1-P(x=0)

The probability of at least once is given as 63/64 we need to find the number of times we need to send the massage.

(63)/(64)=1-(n!)/(0!(n-0)!)(1)/(2)^0(1)/(2)^(n-0)

(63)/(64)=1-(n!)/(n!)(1)/(2)^(n)

(63)/(64)=1-(1)/(2)^(n)

(1)/(2)^(n)=1-(63)/(64)

(1)/(2)^(n)=(1)/(64)

By comparing the value number we find that the value of n should be 6.

Hence, 6 times we need to transmit the message over this unreliable channel so that with probability 63/64.


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A statistic is a characteristic of a sample while a parameter is usually an unknown population parameter?True

False

Answers

This should be Correct-

Answer:

True

Explanation:

A statistic is a characteristic of a sample, a portion of the target population. A parameter is a fixed, unknown numerical value, while the statistic is a known number and a variable which depends on the portion of the population.

Parameter Definition: a quantity or statistical measure that, for a given population, is fixed and that is used as the value of a variable in some general distribution or frequency function to make it descriptive of that.

Population: The mean and variance of a population are population parameters.

Statistic Definiton: A statistic or sample statistic is any quantity computed from values in a sample that is used for a statistical purpose. Statistical purposes include estimating a population parameter, describing a sample, or evaluating a hypothesis. The average of sample values is a statistic.

The answer is: true

Hope this helps! Happy holidays;)

9 + 1.34 + .5 (3.50 +1.74) How would you simplify the expression? Explain your steps.

Answers

1. Using PEMDAS, I would first solve the equation inside the parenthesis
(3.50+1.74)= 5.24
Now the equation is:
9+1.34+.5(5.24)
2. Multiply .5(5.24)
9+1.34+2.62=
12.96

Why is it important to have high
quality audio files

Answers

Answer:

TO HEAR BETTER

Because as quality increases the tone increases

What is the greatest common factor of 12 and 90?

Answers

The first step to find the gcf of 12 and 90 is to list the factors of each number. The factors of 12 are 1, 2, 3, 4, 6 and 12. The factors of 90 are 1, 2, 3, 5, 6, 9, 10, 15, 18, 30, 45 and 90.  So the greatest common factor is 90 Buddy.

An angelfish was 1 1/2 inches long when it was bought. Now it is 2 1/3 inches long.a. How much has the angelfish grown?

b. An inch is 1/12 of a foot. How much has the angelfish grown in feet?

40 points!

Answers

A)

Earlier, The length of the angelfish  = 1 (1)/(2) inches

Now, the length of angelfish = 2 (1)/(3) inches

We have to determine the grown length of angelfish

=  2 (1)/(3) -  1 (1)/(2)

= (7)/(3)- (3)/(2)

LCM of '2' and '3' is '6',

= (14-9)/(6)

= (5)/(6) inch

Therefore, the angelfish has grown by (5)/(6) inch.

B)

We have to determine the increased length of angelfish in feet.

Since 1 inch = (1)/(12) foot

So, (5)/(6) inch = (5)/(6) * (1)/(12) = (5)/(72)

= 0.069 foot.

The answer for A is 5/6 inches.
2 1/3 - 1 1/2 = 2 2/6 - 1 3/6

= 2 + 6 / 6 - 1 3/6 = 8/6 - 1 3/6 = 5/6

The answer for B is 0.0694 feet.
Greetings!

A manufacturer of college textbooks is interested in estimating the strength of the bindings produced by a particular binding machine. Strength can be measured by recording the force required to pull the pages from the binding. If this force is measured in pounds, how many books should be tested to estimate the average force required to break the binding to within 0.08 lb with 99% confidence? Assume that σ is known to be 0.72. (Exact answer required.)

Answers

Answer:

538 books should be tested.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = (1-0.99)/(2) = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

M = z*(\sigma)/(√(n))

In which \sigma is the standard deviation of the population and n is the size of the sample.

How many books should be tested to estimate the average force required to break the binding to within 0.08 lb with 99% confidence?

n books should be tested.

n is found when M = 0.08

We have that \sigma = 0.72

M = z*(\sigma)/(√(n))

0.08 = 2.575*(0.72)/(√(n))

0.08√(n) = 2.575*0.72

√(n) = (2.575*0.72)/(0.08)

(√(n))^(2) = ((2.575*0.72)/(0.08))^(2)

n = 537.1

Rounding up

538 books should be tested.